<u>Answer:</u> The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
<u>Explanation:</u>
We are given:
Moles of oxygen gas = 9.3 moles
The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:
<u>For hydrogen sulfide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide
So, 9.3 moles of oxygen gas will react with = of hydrogen sulfide
<u>For sulfur dioxide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas produces 2 moles of sulfur dioxide
So, 9.3 moles of oxygen gas will produce = of sulfur dioxide
Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
The presence of H3O+ is the hydronium ion, and one definition of an acid is something that donates a proton (H+). HCl in this case does just that. Basic solution forming with NaOH and water: ... NaOH + H2O ==>Na+ + OH- so it donates or produces OH- ions, thus making a basic solution
The answer is (B.) PROTIENS.
Electron is the correct answer :D