Answer:
Increases
Explanation:
Both acids and bases can measured
using the pH or pOH scale. Both
scales provide a measure of either
the H+ concentration or the OHconcentration.
Notice that each scale shows were
acids and bases both are located.
• When acids are measured, the
pH is less than 7, but the pOH
is greater than 7.
• When bases are measured,
the pH is greater than 7, but
the pOH is less than 7.
Both scales are dependent on what
ion you are measuring
Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g
Answer:
mass of carbon = 0.438g
Explanation:
mass percentage = 0.00438%
<u>Answer:</u>
Now it is given here that there are 325 tubes that are manufactured for sunscreen. And we also know that the percentage of sunscreen in benzyl salicylate is 2.5% here in one tube we have 2 Oz of sunscreen.
<u>Explanation:</u>
So sunscreen in 325 tubes will be 2 x 325= 650 Oz. Since we know the amount of sunscreen in 325 tubes the amount of Benzyl salicylate in all 325 tubes will be 650 x 0.025 = 16.25 Oz
<em>Now this can be converted into kg as 0.46 kg</em>.
Explanation:
1 literThe total of water is equal to 1000.0 g of water
we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water
1. For that find the molar mass
Na: 2 x 22.99= 45.98
S: 32.07
O: 4 x 16= 64
The total molar mass is 142.05
We have to find the number of moles, y
To find the number of moles divide 10.0g by 142.05 g/mol.
So the number of moles is 0.0704 moles.
For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.
The molarity would end up being 0.0704 M
The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter
