How many grams of H2O are in 3.00 moles of H2O?
1 answer:
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Answer: 16.32 g of as excess reagent are left.
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of require = 1 mole of
Thus 0.34 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
Moles of left = (0.68-0.17) mol = 0.51 mol
Mass of
Thus 16.32 g of as excess reagent are left.
Answer:
<h2>4.55 L</h2>Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we're finding the new volume
We have
We have the final answer as
<h3>4.55 L</h3>Hope this helps you