Question

Three fourths a number plus 8 is 20 less than the number

Answer 1

Answer:

Equation:  $\frac{3}{4}n+8=n-20$

Solve for n:  n = 112

Step-by-step explanation:

To first set up the equation, you need to look at the verbal description and translate into numbers and operations:

'three fourths a number' =  $\frac{3}{4} n$

'plus 8' = + 8

'is' =

'20 less' = - 20

'the number' = n

Put the expressions together:

'three fourths a number plus 8':  $\frac{3}{4}n+8$

'20 less than the number': n - 20

Set them equal to each other and solve: $\frac{3}{4}n+8=n-20$

Add 20 to both sides: $\frac{3}{4}n+8+20=n-20+20$

Subtract $\frac{3}{4}n$ from both sides: $\frac{3}{4}n-\frac{3}{4}n+28=n-\frac{3}{4}n$

Multiply both sides by $\frac{4}{1}$: $\frac{4}{1}28=\frac{1}{4}n\frac{4}{1}$

Solve for n:  n = 112