All categories

2 years ago

What is the percent increase from 65.6 to 82.2?

Mathematics

2 answers:

Salsk061 [2.6K]2 years ago

8 0

Around 20%........ You can use a calculator

Simora [160]2 years ago

7 0

Increase = 82.2 - 65.6 = 16.6 Percent increase = 16.6/65.6 * 100% = 0.24 * 100 % = 24%

You might be interested in

What is the Greatest Common Factor for expression 32x+16y-48?

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

16 (2x + y - 3)

5 0

2 years ago

You roll 2 dice. What is the probability that the sum of the dice is even or the sum of the dice is greater than 6?

Daniel [21]

How many sides does the dice have...

8 0

2 years ago

Read 2 more answers

Heather, Eric, and Chang sent a total of 116 text messages over their cell phones during the weekend. Chang sent 3 times as many

notka56 [123]

Answer:

Step-by-step explanation:

Declaration

Let Heather's number of messages = x

Let Eric's number of messages = x + 9

Let Chang's number of messages = 3(x +9)

Equation

x + x + 9 + 3(x + 9) = 116

Solution

x + x + 9 + 3(x + 9) = 116 Remove the brackets

x + x + 9 + 3x + 27 = 116 Combine like terms

x + x + 3x + 9 + 27 = 116

5x + 36 = 116 Subtract 36 from both sides

5x + 36 - 36 = 116 - 36 Combine

5x = 80 Divide both sides by 5

5x/5 = 80/5

x = 16

Answer

Heather = 16

Eric = 16 + 9 = 25

Chang = 3*25 = 75

5 0

1 year ago

Find the product of 17892 and 36

solniwko [45]

The answer to 17892•36 is 644,112

6 0

3 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago