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3 years ago

5/6 + (-3/4) please help me out quick thank you

Mathematics

1 answer:

zubka84 [21]3 years ago

5 0

10/12 - 9/12 = 1/12 is the answer. you had to change the denominator so that they are the same

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Question 5 Unsaved

Otrada [13]

We can use the compound interest formula

F=P(1+i)^n

where

F=Future value of investment to be found

P=present value of investment ($1000)

i=interest per period (1/4 year)=0.04/4=0.01

n=number of periods (3 years * 4 quarters = 12)

Substitute or "Plug in" values, so to speak,

F=1000*(1+0.01)^12

use a calculator to do the sum

=1126.83 (to the nearest cent, and use the proper rounding rules)

3 0

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

aliina [53]

C
explanation:
6(1)-39=-33
6(2)-39=-27

8 0

3 years ago

9. Cal is buying T-shirts and shorts. T-shirts

damaskus [11]

Hey there!

Step By Step:

Well so we know that 12 is about half of an 25. So what we are gonna do is to buy 3 of 12$ and 2 of 25$.

3x12=36 and 2x25=50.

With adding those two last numbers, you’ll get $86.

Graph would be down below.

Hope it helps :D

3 0

3 years ago

Answer this geometry question

Basile [38]

The measure of the angle formed by 2 chords that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.
m∠RST = (143+33)/2 = 176/2 = 88°

6 0

3 years ago

Graph y = x2 + 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum. (0, 2); maximum (0, 2); minimum (2,

miskamm [114]

Answer:

$(0,2)$ ; minimum

Step-by-step explanation:

Given:

The function is, $y=x^{2}+2$

The given function represent a parabola and can be expressed in vertex form as:

$y=(x-0)^{2}+2$

The vertex form of a parabola is $y=(x-h)^{2}+k$ , where, $(h,k)$ is the vertex.

So, the vertex is $(0,2)$ .

In order to graph the given parabola, we find some points on it.

Let $x=-2,y=(-2)^{2}+2=4+2=6$

$x=-1,y=(-1)^{2}+2=1+2=3$

$x=0,y=(0)^{2}+2=0+2=2$

$x=2,y=(2)^{2}+2=4+2=6$

$x=1,y=(1)^{2}+2=1+2=3$

So, the points are $(-2,6),(-1,3),(0,2),(1,3),(2,6)$ .

Mark these points on the graph and join them using a smooth curve.

The graph is shown below.

From the graph, we conclude that at the vertex $(0,2)$ , it is minimum.

8 0

3 years ago