Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
sin = 3/7
1 = sin²0 + cos²0
cos²0 = 1 - 9/49
cos²0 = 40/49
cos0 = √(40) / 7
since its in Quadrant 2 the sin is positive and cos is negative
cos0 = - √(40) / 7
Step-by-step explanation:
the first one is 2 that appears most while the second is 20 and 3
1 gal because there is 16 cups in a gallon
A = l*w
A = 4*12 = 48cm^2
The area of the rectangle is 48cm^2 (cm squared)
