Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
Answer:
c i think
Step-by-step explanation:
F(x) = 2x² - x
f(3) = 2(3)² - 3
f(3) = 2(9) - 3
f(3) = 18 - 3
f(3) = 15
f(x) = 2x² - x
f(5) = 2(5)² - 5
f(5) = 2(25) - 5
f(5) = 50 - 5
f(5) = 45
The answer is C.
Answer:
del
Step-by-step explanation:
d