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3 years ago

34÷3=? dcvsfregbrfdewqsdcfvgrbtrfdcfvgb

Mathematics

2 answers:

castortr0y [4]3 years ago

8 0

Answer: 11.33333333333333

drek231 [11]3 years ago

3 0

34 divided by 3=11.3333333
Long division: 34 divided by 3= 11 with a remainder of 1

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3 years ago

A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin

maks197457 [2]

Answer:

(a) $\sum x_i=56.68$ and $\sum x_i^2=197.46$

(b) The sample variance is $s^2=0.530$ and the sample standard deviation is $s=0.728$

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

$\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68$

and the sum of their squares is

$\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46$

(b)

The sample variance, denoted by $s^2$ , is given by

$s^2=\frac{S_{xx}}{n-1}$

where $S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}$

Applying the above formula we get that

$S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482$

$s^2=\frac{8.482}{17-1}=0.530$

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

$s=\sqrt{s^2}$

Applying the above formula we get that

$s=\sqrt{0.530}=0.728$

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3 years ago