Using the Unit Rate to Solve a Problem

Help me please an thank you

svetoff [14.1K]

Answer:

The angle that us congruent to angle 6 is angle 2 and angle 3.

4 0

3 years ago

A right triangle has side lengths a, b, and c as shown below.

Musya8 [376]

Answer:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Step-by-step explanation:

Given that

A right triangle has side lengths a, b, and c

Because you did not attached photo of the right triangle so I will assume that:

Side a is the adjacent (A)
Side b is the opposite (O)
Side c is the hypotenuse (H)

(Please have a look at the attached photo)

To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.

$\sin x = \frac{O}{H}\\\cos x = \frac{A}{H}\\\tan x = \frac{O}{A}$

EX: the sine of x is equal to the side opposite of angle x over the hypotenuse. Hence, we have the expressions of the trigonometric functions as shown below:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Hope it will find you well

4 0

3 years ago

A five-digit number is represented by ABCDE. If we add the number 1 in front of ABCDE, then the product of 1ABCDE and 3 will be

IceJOKER [234]

Answer:

ABCDE = 42857

Step-by-step explanation:

First, we will use logic. The only number that when it's multiplied by 3, gives 1 at the end is 7, so E should be 7, so:

1ABCD7 * 3 = ABCD71

If 3 times 7 is 21, we carry two, so, the next number by logic, cannot be 1, because 3*1 = 3 + 2 = 5, it's not 7, so, it should be another number, like 5.

5*3 = 15 + 2 = 17 and we carry one. So this number fix in the digit, and D = 5.

We have now: 1ABC57 * 3 = ABC571

Letter C, we have to get a number that when it's multiplied by 3 and carry one, gives 5. In this case 8, because: 3 * 8 = 24 + 1 = 25 and carry two. D = 8.

So far: 1AB857 * 3 = AB8571

Now, the same thing with B. If we multiply 3 by 2, and carry two we will have 8 so: 3 * 2 = 6 + 2 = 8. B = 2

1A2857 * 3 = A28571

Finally for the last number, a number multiplied by 3 that hold the 1 as decene, In this case, the only possibility is 4, 3 * 4 = 12 so:

142857 * 3 = 428571

7 0

3 years ago

1Find an equation of the line perpendicular to the graph of yx + 5 that has a y-4intercept of (0, -3). Write your equation in sl

lianna [129]

Given data:

The given equation of line is y=x/4+5.

The given y-intercept is (0,c)=(0,-3).

The standard equation of line is,

y=mx+c

Compare the given equation with the above expression.

m=1/4

The expression for the slope which is perpendicular to the given line.

$\begin{gathered} m^{\prime}\times m=-1 \\ m^{\prime}(\frac{1}{4})=-1 \\ m^{\prime}=-4 \end{gathered}$

The equation of the line which is perpendicular to the given line is,

$\begin{gathered} y=m^{\prime}x+c \\ =-4x-3 \end{gathered}$

Thus, the line which is perpendicular to the given line is y=-4x-3.

4 0

1 year ago

Select the correct answer. Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form q(x)+r(x)/b(x).

daser333 [38]

1 step: Divide the polynomial $x^3+10x^2+13x+39$ by the polynomial $x^2+2x+1$ with remainder:

$x^3+10x^2+13x+39=(x^2+2x+1)(x+8)+(-4x+31).$

Here $x+8$ is quotient and $-4x+31$ is remainder.

2 step: Substitute previous result into the fraction:

$\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=\dfrac{(x^2+2x+1)(x+8)+(-4x+31)}{x^2+2x+1}=\\ \\=\dfrac{(x^2+2x+1)(x+8)}{x^2+2x+1}+\dfrac{-4x+31}{x^2+2x+1}=(x+8)+\dfrac{-4x+31}{x^2+2x+1}.$

Answer: correct choice is A.

8 0

3 years ago