If sin(x) = 3/5, what is sin(2x)

Mathematics

2 answers:

alukav5142 [94]3 years ago

6 0

Answer:

24/25

Step-by-step explanation:

Trig functions relate the angle of a triangle with the sides of that triangle (right triangle)

sin(x)= 3/5 (opposite/ hypotenuse) (25=9-x^2, using pythag. theorem, remaining side= 4)

now, cos(x)= 4/5

now, the double angle identity states:

sin2x= 2sinxcosx

so,

sin2x= 2 * (3/5) * (4/5) =

24/25

scZoUnD [109]3 years ago

3 0

<h3>Answer: 24/25</h3>

====================================================

Explanation:

If sin(x) = 3/5, then cos(x) = 4/5 through the use of the trig identity

sin^2(x) + cos^2(x) = 1

This is assuming that x is in quadrant Q1.

Plug those values into the identity below and simplify.

sin(2x) = 2*sin(x)*cos(x)

sin(2x) = 2*(3/5)*(4/5)

sin(2x) = 24/25

You might be interested in

Qual o nome do instrumento usado para medir os graus de um ângulo?

Aleks [24]

English: What is the name of the instrument used to measure the degrees of an angle?

responder:
transportador

7 0

4 years ago

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

vovikov84 [41]

Answer:

The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.

Step-by-step explanation:

The question is incomplete.

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by

$P=n^2-2n-3$

where n is the number of key rings in thousands.

Find the number of key rings sold on a particular day when the total profit is $5,000.

We have the profit defined by a quadratic function.

We have to calculate n, for which the profit is $5,000.

$P=n^2-2n-3=5\\\\n^2-2n-8=0$

We have to calculate the roots of the polynomial we use the quadratic equation:

$n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\n= \frac{-2\pm\sqrt{4-4*1*(-8)}}{2}= \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{36}}{2} =\frac{-2\pm6}{2} \\\\n_1=(-2-6)/2=-8/2=-4\\\\n_2=(-2+6)/2=4/2=2$