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3 years ago

I need the answer to thisssssss im confused please help thank youuuuuu

Mathematics

1 answer:

77julia77 [94]3 years ago

3 0

Answer:

light blue

Step-by-step explanation:

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At the movie theater, there are 4 action movies, 2 horror movies, 5 comedy movies, and 2 animated movies scheduled for the day.

sergiy2304 [10]

I know the answer it is 31 percent because 4/13 is 3.25 and it says to the nearest percent so it is 31 percent please give me thanks and 5 stars aand brainliest answer

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Find the measure of angle A

blagie [28]

Answer:

43°

Step-by-step explanation:

(x + 53)° + (x + 74)° + 73° = 180°

(x + 53 + x + 74)° = 180° - 73°

(2x + 127)° = 107°

2x + 127 = 107

2x = 107 - 127

2x = - 20

x = - 20/2

x = - 10

$m\angle A = (x +53)\degree \\\\m\angle A = (-10 +53)\degree \\\\m\angle A = 43\degree \\\\$

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3 years ago

Please help!!!I'm confused

IceJOKER [234]

Any rhombus has the same length for all for sides, so:
x + 14 = 3x +4
So, we get x = 5

Now, we can write
x + 14 = 8y
Since x = 5,

19 = 8y
so y = 19/8 = 2.375

You can take any one of the equations and substitute the value of x or y in. The length is 19

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Martha is constructing the circumscribed circle for △RST. She has already used her compass and straightedge to complete the part

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Place the point of the compass on the intersection of AB¯¯¯¯¯ and CD¯¯¯¯¯ and extend the compasses to point R.

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A cash register contains 5 $10 bills and 3 $5 bills. you randomly pick 4 bills.

kobusy [5.1K]

a. The probability of picking exactly two $10 bills is $\frac{3}{7}$

b. The probability of picking at most one $5 bill is $\frac{1}{2}$

Explanation

Number of $10 bills $= 5$

and number of $5 bills $= 3$

Total number of bills= 5+3 = 8. You need to randomly pick 4 bills, so the total possible outcome $= ^8C^4$

a.

For getting exactly two $10 bills, you need to pick two $10 bills and two $5 bills. That means we will pick two $10 bill from 5 bills and two $5 bills from 3 bills.

So, the probability $=\frac{(^5C^2)*(^3C^2)}{^8C^4} =\frac{10*3}{70}=\frac{30}{70}=\frac{3}{7}$

b.

For getting at most one $5 bill, you need to pick either zero or one $5 bill.

If you pick zero $5 bill, that means there are four $10 bills

and if you pick one $5 bill, that means there are three $10 bills.

So, the probability $=\frac{(^3C^0*^5C^4)+(^3C^1*^5C^3)}{^8C^4}=\frac{(1*5)+(3*10)}{70}=\frac{5+30}{70}=\frac{35}{70}=\frac{1}{2}$

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4 years ago