Answer:
2016
Step-by-step explanation:
To solve this problem, let us find the prime factors of the given numbers:
96
8 x 12
2 x 2 x 2 2 x 2 x 3
2⁵ x 3
144
12 x 12
2 x 2 x 3 2 x 2 x 3
2⁴ x 3²
126
2 x 63
2 7 x 9
2 3 x 3 x 7
2 x 3² x 7
So, the lowest common multiple = 2⁵ x 3² x 7 = 2016
M<BAD = m<BAC + m<CAD
m<BAD = 20 + 15
m<BAD = 35
<span>Angle Addition Postulate
answer
</span><span>Angle Addition Postulate</span>
Answer:
mABD=24
mDBC=24
Step-by-step explanation:
First, set up x+15 and 4x-12 as equivalent equations
Subtract x from both sides to get 3x-12=15
Add 12 to get 3x=27
x=9
Plug 9 into the original equations representing the measurements of angles
You should get 24 for both because bisected means both are congruent
X= 44 and Y= 46 . PLEASE MARK BRANLIEST
Answer:
The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 31 - 1 = 30
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.457
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 27.5 - 1.3 = 26.2 years
The upper end of the interval is the sample mean added to M. So it is 27.5 + 1.3 = 28.8 years
The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.