Will give brainliest! which of the following correctly shows the beginning steps to solve this equation?

Mathematics

1 answer:

padilas [110]3 years ago

7 0

2(7x - 3) = 9

step 1 : distribute thru the parenthesis......14x - 6 = 9
step 2 : add 6 to both sides.......14x = 15

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Find y. round to the nearest tenth:

Nimfa-mama [501]

Step-by-step explanation:

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4 0

2 years ago

Boyd grows only tomatoes and raspberries in his garden. Last year, he grew 140 pounds of tomatoes and 60 pounds of raspberries.

nadya68 [22]

Answer:

29%.

Step-by-step explanation:

We have been given that Boyd grew 140 pounds of tomatoes and 60 pounds of raspberries. This year, the production, by weight, of tomatoes declined by 20 percent, and the production, be weight, of raspberries declined by 50 percent.

First of all, we will find the weight of tomatoes and raspberries using the given information.

Since the production, by weight, of tomatoes declined by 20 percent, so this year production of tomatoes is 80% of 140 pounds.

$\frac{80}{100}\times 140=0.80\times 140=112$

Since the production, be weight, of raspberries declined by 50 percent, so this year production of raspberries is 50% of 30 pounds.

$\frac{50}{100}\times 60=0.50\times 60=30$

Total production this year: $112+30=142$ pounds.

Now, we will percent decrease formula.

$\text{Percent decrease}=\frac{\text{Initial value-Final value}}{\text{Initial value}}\times 100$

$\text{Percent decrease}=\frac{(140+60)-142}{140+60}\times 100$

$\text{Percent decrease}=\frac{(200)-142}{200}\times 100$

$\text{Percent decrease}=\frac{58}{200}\times 100$

$\text{Percent decrease}=0.29\times 100$

$\text{Percent decrease}=29$

Therefore, the total yield, by weight, of Boyd's garden declined by 29%.

5 0

3 years ago

What is the equation (simplified) the inverse of y=2x^2?

Yuki888 [10]

$2x^2=y\ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=\dfrac{y}{2}\\\\\boxed{x=\sqrt{\frac{y}{2}}}\\\\x=\dfrac{\sqrt{y}}{\sqrt2}=\dfrac{\sqrt{y}\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\to\boxed{x=\dfrac{\sqrt{2y}}{2}}\\\\\\\boxed{f(x)=2x^2\to f^{-1}(x)=\dfrac{\sqrt{2y}}{2}}$