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yarga [219]
3 years ago
14

Need help pls will give you a good rating.

Mathematics
2 answers:
Elanso [62]3 years ago
5 0

Answer:

x+4

.....................

aliina [53]3 years ago
3 0

Answer

\boxed{x + 4}

Option C is the correct option

Step by step explanation

Let's find the expression which represents the length of the box:

\mathsf{length \times width \times height \: of \: prism \:  =  \: volume \: of \: prism}

\mathsf{lengh \times \: (x - 1) \times (x + 8) =  {x}^{3}  + 11 {x}^{2}  + 20x - 32}

\mathsf{length  =  \frac{ {x}^{3}  + 11 {x}^{2} + 20x - 32 }{(x - 1)(x + 8)} }

Write 11x² as a sum

\mathsf{ =  \frac{ {x}^{3}  -  {x}^{2} + 12 {x}^{2}  + 20x - 32 }{(x - 1)(x + 8)} }

Write 20x as a sum

\mathsf{  = \frac{ {x}^{3}  -  {x}^{2}  + 12 {x}^{2} - 12x + 32x - 32 }{(x - 1)(x  + 8)}}

Factor out x² from the expression

\mathsf{  = \frac{ {x}^{2}(x - 1) + 12 {x}^{2} - 12x + 32x - 32  }{(x - 1)(x + 8)} }

Factor out 12 from the expression

\mathsf{ =  \frac{ {x}^{2}(x - 1) + 12x(x - 1) + 32x - 32 }{(x - 1)(x + 8)} }

Factor out 32 from the expression

\mathsf{  = \frac{ {x}^{2}(x - 1) + 12x(x - 1) + 32(x - 1) }{(x - 1)(x + 8)} }

Factor out x+1 from the expression

\mathsf{   = \frac{(x - 1)( {x}^{2} + 12x + 32) }{(x - 1)(x + 8)}  }

Factor out 12x as a sum

\mathsf{ =  \frac{(x - 1)( {x}^{2} + 8x + 4x + 32) }{(x - 1)(x + 8)} }

Reduce the fraction with x-1

\mathsf{  = \frac{ {x}^{2} + 8x + 4x + 32 }{(x + 8)} }

Factor out x from the expression

\mathsf{  = \frac{x(x + 8)  + 4x + 32}{(x + 8)} }

Factor out 4 from the expression

\mathsf{  = \frac{x(x + 8)  + 4(x + 8)}{x + 8} }

Factor out x+8 from the expression

\mathsf{   = \frac{(x + 8)(x + 4)}{x + 8} }

Reduce the fraction with x+8

\mathsf{ = x + 4}

hence, x+4 is the expression that represents the length of a box.

Hope I helped!

Best regards!

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