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Zigmanuir [339]
3 years ago
5

Answered

Mathematics
1 answer:
ra1l [238]3 years ago
8 0

Answer:

the answer is 10

Step-by-step explanation:

if x=7

and y=x+3 then y=7+3

y=10

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Movies at the rental store are $3.75 each. Snacks and drinks are $1.89 each. Round each amount to the nearest dollar to estimate
hodyreva [135]

Answer:

$14.00

Step-by-step explanation:

First you round 3.75 to 4.00 because 7 is greater than 5 so it would turn the 3 to 4 than add the zeros it's 4.00. Second You multiply by three so 4.00 × 3 you will get 12.00. Than you round 1.89 to 2.00 because 8 is greater than 5 so it would turn to the 1 to the 2 than add the zeros it's 2.00. Finally you add them together and get $14.00

4 0
2 years ago
Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
HELPPPP PLEASEEEEE !!!!!What is the surface area of the composite solid?
Bingel [31]

Answer: answer C is correct or 1,808 meters squared

Step-by-step explanation:

4 0
4 years ago
A poster is shown below: A rectangle is shown. The length of the rectangle is labeled 10 feet. The width of the rectangle is lab
makkiz [27]
The enlarged length is (3/2)*10 ft = 15 ft.
The enlarged width is (3/2)*4 ft = 6 ft.

The dimensions of the enlarged poster are ...
  <span>6 ft by 15 ft</span>
6 0
4 years ago
Read 2 more answers
5x(2x-y) -3y(2+3x) expand and simplify​
OleMash [197]

Answer:

10x² - 14xy -6y

Step-by-step explanation:

5x(2x-y)-3y(2+3x)

10x²-5xy-6y-9xy

10x² - 14xy - 6y

5 0
3 years ago
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