Answer:
f(- 6) = 9
Step-by-step explanation:
to evaluate f(- 6), substitute x = - 6 into f(x)
f(- 6) = -
× - 6 + 5
= -
+ 5 = 4 + 5 = 9
Answer: A. 8x+13
Step-by-step explanation:
9+4(2x-1)+8
Use distributive property
9+8x-4+8
Combine like terms
8x+13

so
(this is wrong because
)
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
Answer:
The correct option is 4. Neither A nor B represents a function.
Step-by-step explanation:
The given sets of ordered pairs are


A set of ordered pairs represents a function if there exist unique outputs for all inputs. It means for each values of x there exist, a unique value of y.
In set A the value of y-coordinates are -5 and 7 at
.
At x=8, there exist more than one value of y, so the set A is not a function.
In set B the value of y-coordinates are -4 and -2 at
.
At x=7, there exist more than one value of y, so the set B is not a function.
Therefore neither A nor B represents a function and option 4 is correct.