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3 years ago

PLEASE HELP 30 PTS!!! Select ALL the correct answers. Which expressions are equivalent to the following?

Mathematics

1 answer:

Oksanka [162]3 years ago

7 0

Answer:

D: -5(-6x^2 + x + 2)

E: 5(2x + 1)(3x − 2)

Step-by-step explanation:

The first two answer choices have incorrect constants (25 and 3 vs -10). A factor of 5 is removed from the remaining answer choices, so let's remove a factor of 5 and see what we get:

30x^2 -5x -10 = 5(6x^2 -x -2)

An additional x cannot be factored from the expression, so choice C can be eliminated.

Multiplying each of these factors by -1 will make the product correspond to answer choice D.

Factoring will make it correspond to answer choice E, best verified by finding the x-term of the product of the binomial factors:

E: 2x(-2) +1(3x) = -x, as required

F: 2x(2) -1(3x) = x, wrong sign

The equivalent expressions are those of choices D and E.

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3 years ago

I’ll give the Brainliest to who answers this question with a reasonable explanation.

SSSSS [86.1K]

Answer:

31136

Step-by-step explanation:

To find the how much an number increased by a percent. Divide the percent by 100. 23/100=0.23.

Then multiply 0.23 by the original number which is 25,314. Which gives us about 5822.

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2 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

8 0

3 years ago

3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d

pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
$\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}$

Where A is the final amount, P is the initial amount, r is the interest rate, n is the number of times compounded per year, and t is the number of years.

To obtain $4000 after two years, let A = 4000 and t = 2.

Because the account pays 3% interest compounded monthly, r = 0.03 and n = 12.

Substitute and solve for P:

$\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}$

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

$\displaystyle A = Pe^{rt}$

Where e is Euler's number.

Hence, let A = 4000, r = 0.04 and t = 2. Substitute and solve for P:

$\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}$

In conclusion, about $3692.47 should be deposited.

8 0

2 years ago

Write the following equation in standard form: y + 4 = -3(x + 2)

Irina18 [472]

Answer:

-3x-y=10

Step-by-step explanation:

y+4=-3(x+2)

y+4=-3x-6

y=-3x-6-4

y=-3x-10

-3x-y=10

5 0

3 years ago