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monitta
3 years ago
6

Divide to find the quotient. Please help ! Just tell me what write in boxes

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer: 8 r 2

Step-by-step explanation:

The closest thing that goes into 26 is 24, which goes into 3 8 times. Subtract 24 from 26, and you are left with 2. The 2 you are left with will be your remainder.

Umnica [9.8K]3 years ago
6 0

Answer:

8 R 2

Step-by-step explanation:

8 x 3= 24

26-24= 2

so, 8 R 2

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The assembly line that produces an electronic component of a missile system has historically resulted in a 2% defectiverate. a r
sattari [20]

<span>Defective rate can be expected to keep an eye on a Poisson distribution. Mean is equal to 800(0.02) = 16, Variance is 16, and so standard deviation is 4.
X = 800(0.04) = 32, Using normal approximation of the Poisson distribution Z1 = (32-16)/4 = 4.
P(greater than 4%) = P(Z>4) = 1 – 0.999968 = 0.000032, which implies that having such a defective rate is extremely unlikely.</span>

<span>If the defective rate in the random sample is 4 percent then it is very likely that the assembly line produces more than 2% defective rate now.</span>

3 0
3 years ago
What is the lcm of 9202 and 23,782?? will mark brainliest
Grace [21]

Answer:

109,420,982

Step-by-step explanation:

6 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
Last week caroline worked 8 hours each day and she worked 5 days that week she earned $440 pounds so per hour she earned £11
IRISSAK [1]

Answer:

30%

Step-by-step explanation:

this week:

4 × 7 = 28 hours

earns: 28 × 11 = £308

reduction: 440 - 308 = 132

% reduction

132/440 × 100

30%

5 0
3 years ago
Which pair of transformations moves quadrilateral 1 to quadrilateral 2?
malfutka [58]

Translate it 8units to the right then reflect it over the line y=-3

Why?

  • We can see the Quadrilateral is in Quadrant 3.
  • If we translate it by 8units right it come to Quadrant 4.
  • Now reflect it over line y=-3
  • we will get Quadrilateral 2
6 0
3 years ago
Read 2 more answers
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