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Inessa05 [86]
3 years ago
6

Prove sin^3z*cos^2z=sin^3z-sin^5z

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0
Left hand side
sin^3z × ( 1 - sin^2z ) = RHS
let sin z = y
y^3 × ( 1 - y^2 ) = RHS
y^3 - y^6 = RHS
sin^3z - sin^6z = RHS

the answer at RHS should be to the power of 6 . u better check it next time
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