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Fynjy0 [20]
2 years ago
11

How many cubes with edge lengths of 1/4 in. will it take to fill the prism?

Mathematics
1 answer:
Ulleksa [173]2 years ago
3 0

Answer:

1560

Step-by-step explanation:

First (2 1/2)/(1/4) = (5/2)(4) = 20/2 = 10

Next, 3/(1/4) = 3(4) = 12

Lastly, (3 1/4)/(1/4) = (13/4) x 4 = 52/4 = 13

This means we need 10 rows of 12, 13 high. 10(12)(13) = 1560 cubes.

Another way is to multiply 2 1/2 x 3 x 3 1/4 = 5/2 x 3 x 13/4 = 195/8

A 1/4 inch cube is 1/4 x 1/4 x 1/4 for a volume of 1/64

(195/8)/(1/64) = (195/8)(64) = 1560 cubes.

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Explain how the function y=-1/3|x+2|+5 is transformed from the original function of y=-1/3|x|.
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The original function of y = -1/3|x| was translated 2 units to the right and 5 units up.

<h3>The types of transformation.</h3>

In Mathematics, there are four (4) main types of transformation and these include the following:

  1. Dilation
  2. Rotation
  3. Reflection
  4. Translation

<h3>What is a translation?</h3>

In Mathematics, the translation of a geometric figure (shape) to the right simply means adding a digit to the numerical value on the x-coordinate (x-axis) of the pre-image of a function while a geometric figure (shape) that is translated up simply means adding a digit to the numerical value on the y-coordinate (y-axis) of the pre-image.

In this scenario, the original function was shifted 2 units to the right and then shifted 5 units up to produce the new function as follows:

Original function (x, y)    →     New function (x + 2, y + 5)

y = -1/3|x|                         →        y = -1/3|x + 2| + 5

Read more on translation here: brainly.com/question/20720324

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2 years ago
Write an explicit rule in function form for the sequence represented by the given terms.
hram777 [196]

Answer:

The general relation about a geoemtric sequence is

a_{n}=a_{1}r^{n-1}

For the first sequence, we have

3=a_{1}r^{5-1}

147=a_{1}r^{7-1}

Which is a system of equations. We can isolate a variable in the first equation to replace that expression into the second equation.

a_{1}=\frac{3}{r^{4} }

147=\frac{3}{r^{4}  }r^{6}

r^{2}=\frac{147}{3}\\  r=\sqrt[2]{49}\\r=7

Now, we replace this value to find the other one

3=a_{1}(7)^{4}\\ a_{1}=\frac{3}{2401}

Therefore, the explicit rule function is

a_{n}=\frac{3}{2401}  \times (7)^{n-1}

Now, we use the same process for the second sequence.

10=a_{1}r^{3-1}  \\a_{1}=\frac{10}{r^{2} }

The second equation is

1440=a_{1}r^{5-1}\\a_{1}=\frac{1440}{r^{4} }

Now, we solve the following expression

\frac{10}{r^{2} }=\frac{1440}{r^{4} }

We solve for r

\frac{r^{4} }{r^{2} }=\frac{1440}{10}\\r^{2}=144\\ r=\sqrt{144} \\r=12

Then

a_{1}=\frac{10}{(12)^{2} }  =\frac{10}{144}=\frac{5}{72}

Therefore, the function that models the second sequence is

a_{n}=\frac{5}{72} \times (12)^{n-1}

Notice that a_{n} is the dependent variable and n is the independent variable.

5 0
3 years ago
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