By algebraic handling we find that the unique solution of the system of linear equations is: (x, y, z) = (- 2, 4, 3). (Correct choice: A)
<h3>What is the nature of a system of linear equations?</h3>
If the system of equations has no solutions, then the determinant of the dependent coefficients of the system of linear equations must be zero. Let see:
This determinant can be determined by Sarrus' rule:
D = (1) · (- 1) · (7) + 4 · (- 1) · 1 + (- 1) · 1 · (- 8) - (- 1) · (- 1) · 1 + 4 · 1 · 7 - 1 · (- 1) · (- 8)
D = - 7 - 4 + 8 - 1 + 28 - 8
D = 16
The system of linear equations have at least one solution. This system has only one solution any of the three equations is not a function of the other two. By algebraic handling we find that the unique solution of the system is: (x, y, z) = (- 2, 4, 3).
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If I were you, I would select the first equation to put in y=mx+b form so that you can substitute it in to the second one. What you do is you subtract the x from the left side and bring it over to the right and then you divide everything by 5. The y=mx+b equation is y=-1/5x-7. Then, you substitute this equation into the bottom one so you are now working only with x's. You should distribute and combine like terms. When you distribute and clean it up, at the end you should get 18/5x-14=8. You then add 14 to get 22 on the right side and then multiply that by the reciprocal of the fraction. When you multiply 22 by 5/18, you should get a reduced fraction of 55/9. You then substitute this value into either equation to get the y-value. You should get a y-value of -260/45. Your answer as an ordered pair should be (55/9,-260/45).
Answer:
D. 20 +5(h - 2)
Step-by-step explanation:
This equation represent this problem because you are paid $5 an hour AFTER the first hour because you were paid an initial $20 for the first two hours.
Answer:
A. 45
B. 684
The Least Common Multiple ( LCM ) is also referred to as the Lowest Common Multiple ( LCM ) and Least Common Denominator ( LCD) . For two integers a and b, denoted LCM(a,b), the LCM is the smallest integer that is evenly divisible by both a and b.
LCM= A. 45
Answer:
* 100
Step-by-step explanation:
The voters would be 11+15 and since there were 11 votes for A, that is the equation you should use.
