Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
11 x 12 =132
i think this is the right answer
Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
The answer is currently A so yep thats the answer ok
Answer:
y= -3/4x - 3
Step-by-step explanation:
-3/4 is the slope, so you replace m with the slope.
The y intercept is -3. If x is 4, and y is -6, we can plug that into an equation to find the y intercept. y=mx+b can change to -6= -3/4 * 4 + b. B = -3.
