I hope it helped youuuuuu
I believe this is how you do it
Answer:
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Question:
Yuet solved the equation
for a.
Her steps are shown below.
1. Subtract 2b: 
2. Divide by 6: 
Answer:
In step 1 she needed to add 2b to both sides of the equation.
Step-by-step explanation:
Given:
The above steps shows how Yuet solved an equation
Required:
True statement about Yuet's work
The implication of the statement is to state what Yuet should have done instead of what she did.
In step 1, she subtracted 2b from both sides of the equation; this is wrong.
Instead of subtracting, she ought to add 2b to both sides of the equation.
The correct steps and result is as follows:
1. Add 2b: 
2. Divide by 6: 
Hence, we can conclude that in step 1 she needed to add 2b to both sides of the equation.
Answer:

Step-by-step explanation:
Stare at the numbers. Especially the first two. First one is -11. Second is
. Let's guess you keep multiplying.
. Smells correct, let's confirm with the last one:
. I think we found a pattern. Each element is 7 times the previous one. With some practice you can just write the function, else let's divide by -11 away and let's see what we get:
. Basically, the exponent is 1 less than the value we're evaluating the function. That leads tho the following
