Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Answer:
The teeing area is the place where you throw every shot. The hole is finished when the disc is sucessfully thrown into the basket.
Step-by-step explanation:
Answer:
9x^4 + 2x²y² + y^4
Arrange the terms
9x^4 + y^4 + 2x²y²
making the first two terms into a² + b²
(3x²)² + (y²)² + 2x²y²
use the formula of a² + b² = (a+b)² - 2ab
(3x² + y²)² - 2.3x².y² + 2x²y²
(3x² + y²)² - 6x²y² + 2x²y²
(3x² + y²)² - 4x²y²
(3x² + y²)² - (2xy)²
use the formula a² - b²
(3x² + 2xy + y²) (3x² - 2xy + y²)
Step-by-step explanation:
Answer:
Notebooks cost $2.75 and pens cost $1.10.
He can also buy 3 notebooks.
Step-by-step explanation:
In order to find this, we need to create two equations given each of the situations.
3n + 2p = 10.45
4n + 6p = 17.60
Now to solve for n, multiply the top equation by -3 and add together.
-9n - 6p = -31.35
4n + 6p = 17.60
----------------------
-5n = -13.75
n = 2.75
Now that we have the value of notebooks, we can find the amount for pens using either equation.
3n + 2p = 10.45
3(2.75) + 2p = 10.45
8.25 + 2p = 10.45
2p = 2.20
p = 1.10
Finally, to find the number of notebooks that he can purchase, find the cost of a notebook with 3 pens.
n + 3p
2.75 + 3(1.10)
2.75 + 3.30
6.05
Now divide 22 by that number
22/6.05 = 3.63
Since we can't have fractional notebooks, we round down to 3.
Answer:
its D
Step-by-step explanation:
3r+2(12r+7)<5r-8
3r+24r+14<5r-8
27r+14<5r-8
22<-22r
when you devide by a negative the signs flips so
22/-22>-22/-22r
-1>r
