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lesya692 [45]
2 years ago
5

When sending a rectangular package through the U.S. Postal Service, the combined length and girth (perimeter of the cross sectio

n) cannot exceed 108 inches. Up to what length can a package be if the width and height are 10 and 15 inches?
Mathematics
1 answer:
weqwewe [10]2 years ago
5 0
Let W = width of package
Let H = height of package
Let L = length of package

The perimeter cab be one of the following:
P = 2(L + W),  or
P = 2(L + H)

The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
 2(L + 10) <= 108
 L + 10 <= 54
 L <= 44 in

When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in

To satisfy both of these conditions requires that L <= 39 in.

Answer: 39 inches
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Trisha and Byron are washing and vacuuming cars to raise money for a class trip. Trisha raised $38 washington 5 cars and vacuumi
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Answer:

They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.

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Let the charge of washing a car be 'x'.

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Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.

So framing the above sentence in equation form, we get;

5x+4y=38\ \ \ \ \ equation\ 1

Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.

So framing the above sentence in equation form, we get;

4x+2y=28\ \ \ \ \ equation\2

Now multiplying equation 2 by '2', we get;

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Now we subtract equation 1 from equation 3 and get;

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Now substituting the value of 'x' in equation 1, we get;

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8 0
3 years ago
Solve for x in<br> 2 - 3(x + 4) = 8
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Answer:

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7 0
3 years ago
Read 2 more answers
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