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lesya692 [45]
3 years ago
5

When sending a rectangular package through the U.S. Postal Service, the combined length and girth (perimeter of the cross sectio

n) cannot exceed 108 inches. Up to what length can a package be if the width and height are 10 and 15 inches?
Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
Let W = width of package
Let H = height of package
Let L = length of package

The perimeter cab be one of the following:
P = 2(L + W),  or
P = 2(L + H)

The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
 2(L + 10) <= 108
 L + 10 <= 54
 L <= 44 in

When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in

To satisfy both of these conditions requires that L <= 39 in.

Answer: 39 inches
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If VT=2,what is the length of PT?
marusya05 [52]

Step-by-step explanation:

\underline{ \underline{ \text{Given : }}}

  • Perpendicular ( P ) = VT = 2
  • Base ( b ) = PT
  • \theta =  \tt{60 \degree}

\underline{ \underline{ \text{Solution}}} :

\tt{ \tan(60 \degree)  =  \frac{perpendicualar}{base}}

⟶ \tt{ \sqrt{3}  =  \frac{2}{PT}}

⟶ \tt{ \sqrt{3}  \: PT= 2}

⟶ \tt{PT =  \frac{2}{ \sqrt{3}} }

⟶ \tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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