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jarptica [38.1K]
3 years ago
6

Bonjour pouvez-vous m'aider, j'ai un dm de math niveau 3ème à rendre avant le mardi 14 Septembre, voici l'annoncer:

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

English Translation

Hello can you help me, I have a 3rd level math dm to return before Tuesday September 14th, here is the announcement:

A 25m cable is stretched from the top of a vertical pylon. The ground is considered horizontal. The distance between the base of the pylon and the ground anchoring point of the cable is 4m. Draw a diagram of the situation, determine the height of this pylon, justifying the method used.

Thank you kindly answer me, good evening.

Step-by-step explanation:

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Gala2k [10]

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Step-by-step explanation:

4 0
3 years ago
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Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu
Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4a^{4} - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u²  - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = \frac{1}{4}

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

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Solutions are a = ± 1 , a = ± \frac{1}{2}

7 0
4 years ago
Find the coordinates of the circumcenter of triangle ABC with vertices A(1,4) B(1,2) and C(6,2)
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<span>(3.5, 3) is the circumcenter of triangle ABC. The circumcenter of a triangle is the intersection of the perpendicular bisectors of each side. All three of these perpendicular bisectors will intersect at the same point. So you have a nice self check to make sure your math is correct. Now let's calculate the equation for these bisectors. Line segment AB: Slope (4-2)/(1-1) = 2/0 = infinity. This line segment is perfectly vertical. So the bisector will be perfectly horizontal, and will pass through ((1+1)/2, (4+2)/2) = (2/2, 6/2) = (1,3). So the equation for this perpendicular bisector is y = 3. Line segment BC (2-2)/(6-1) = 0/5 = 0 This line segment is perfectly horizontal. So the bisector will be perfectly vertical, and will pass through ((1+6)/2,(2+2)/2) = (7/2, 4/2) = (3.5, 2) So the equation for this perpendicular bisector is x=3.5 So those two bisectors will intersect at point (3.5,3) which is the circumcenter of triangle ABC. Now let's do a cross check to make sure that's correct. Line segment AC Slope = (4-2)/(1-6) = 2/-5 = -2/5 The perpendicular will have slope 5/2 = 2.5. So the equation is of the form y = 2.5*x + b And will pass through the point ((1+6)/2, (4+2)/2) = (7/2, 6/2) = (3.5, 3) Plug in those coordinates and calculate b. y = 2.5x + b 3 = 2.5*3.5 + b 3 = 8.75 + b -5.75 = b So the equation for the 3rd bisector is y = 2.5x - 5.75 Now let's check if the intersection with this line against the other 2 works. Determining intersection between bisector of AC and AB y = 2.5x - 5.75 y = 3 3 = 2.5x - 5.75 8.75 = 2.5x 3.5 = x And we get the correct value. Now to check AC and BC y = 2.5x - 5.75 x = 3.5 y = 2.5*3.5 - 5.75 y = 8.75 - 5.75 y = 3 And we still get the correct intersection.</span>
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3 years ago
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