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4 years ago

Factor the GCF: −6x3y + 9x2y2 − 12xy3

Mathematics

2 answers:

sweet-ann [11.9K]4 years ago

6 0

-6x^3y + 9x^2y^2 - 12xy^3
-3xy(2x^2) - 3xy(-3xy) - 3xy(4y^2)
-3xy(2x^2 - 3xy + 4y^2)

The answer is C.

Orlov [11]4 years ago

6 0

Answer:

Option C is the answer.

Step-by-step explanation:

We have to factor the GCF of the given expression:

-6x³y + 9x²y² - 12xy³

To get the GCF of the given expression we will find the factors of each term first.

Factors of 6x³y = 2 × 3 × (x) × (x) (x) (y)

Factors of 9x²y² = 3 × 3 × (x) (x) (y) (y)

Factors of 12xy³ = 2 × 2 × 3 × (x) (y) (y) (y)

So the common factor is 3 × (x) (y)

Now we will take out the GCF as a factor of the given expression = 3xy (-2x² + 3xy - 4y² )

= -3xy ( 2x² - 3xy + 4y² )

Option C is the answer.

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Step-by-step explanation:

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4 years ago

Eight more than the product of a number and six equals three

mixas84 [53]

Answer:

8x + 6 = 3

Step-by-step explanation if solving for x

Simplifying

8x + 6 = 3

Reorder the terms:

6 + 8x = 3

Solving

6 + 8x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + 8x = 3 + -6

Combine like terms: 6 + -6 = 0

0 + 8x = 3 + -6

8x = 3 + -6

Combine like terms: 3 + -6 = -3

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Divide each side by '8'.

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Simplifying

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3 0

4 years ago

Read 2 more answers

Consider the given statement. At least one gift in the bag is wrapped.

jasenka [17]

Answer:

The negation to the given statement "At least one gift in the bag is wrapped - true" is " At least one gift in the bag is not wrapped" - False

At least one gift in the bag is not wrapped - False
Not every gift in the bag is wrapped-True
Every gift in the bag is wrapped-False
None of the gifts in the bag are wrapped-False

Step-by-step explanation:

Given statement is At least one gift in the bag is wrapped is true

The negation to the given statement is " At least one gift in the bag is not wrapped" - False

<u>To determine whether the statement is a negation of the given statement is True or False :</u>

<h3> At least one gift in the bag is not wrapped - False </h3><h3> Not every gift in the bag is wrapped-True </h3><h3>Every gift in the bag is wrapped-False </h3><h3>None of the gifts in the bag are wrapped-False</h3>

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3 years ago

Can someone help me I will give the brainliest!!

bogdanovich [222]

Answer & Step-by-step explanation:

2. 4 times (*) f equals (=) 1/2

Equation: 4f=1/2

4 times (*) 1/8 equals (=) 1/2

f = 1/8

3. 832 divided by (/) n equals (=) 16

Equation: 832/n=16

832 divided by (/) 52 equals (=) 16

n = 52

4. 10 subtracted from (-) x equals (=) 6

Equation: 10-x=6

10 - 4 = 6

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Hope this helps ;)

4 0

3 years ago

A painter can paint a building in 15 days and a coworker can do the same job in 10 days. If the first painter starts and 3 days

Sonja [21]

Answer: 7.8 days

<u>Step-by-step explanation:</u>

Painter can get the job done in 15 days so gets $\dfrac{1}{15}$ of the job done in 1 day.

Coworker can get the job done in 10 days so gets $\dfrac{1}{10}$ of the job done in 1 day.

Together, they get $\dfrac{1}{15}+\dfrac{1}{10}$ of the job done in 1 day.

Painter worked for 3 days so completed $\dfrac{1}{15}(3)=\dfrac{1}{5}$ of the job.

That leaves a remaining of $1-\dfrac{1}{5}=\dfrac{4}{5}$ of the job to be completed.

Let x represent the number of days it will take them to work together.

Painter + Coworker = Together

$\dfrac{1}{15}(x)\quad +\quad \dfrac{1}{10}(x)\quad =\quad \dfrac{4}{5}$

Multiply by 30 to eliminate the denominator:

$\dfrac{1}{15}(x)(30) +\ \dfrac{1}{10}(x)(30) = \dfrac{4}{5}(30)$

Simplify and solve for x:

2x + 3x = 24

5x = 24

$x=\dfrac{24}{5}$

x = 4.8

Remember that Painter worked 3 days alone in addition to the 4.8 days they worked together.

So the total time to paint the building is 3 + 4.8 = 7.8

7 0

4 years ago