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3 years ago

Factor the GCF: −6x3y + 9x2y2 − 12xy3

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

6 0

-6x^3y + 9x^2y^2 - 12xy^3
-3xy(2x^2) - 3xy(-3xy) - 3xy(4y^2)
-3xy(2x^2 - 3xy + 4y^2)

The answer is C.

Orlov [11]3 years ago

6 0

Answer:

Option C is the answer.

Step-by-step explanation:

We have to factor the GCF of the given expression:

-6x³y + 9x²y² - 12xy³

To get the GCF of the given expression we will find the factors of each term first.

Factors of 6x³y = 2 × 3 × (x) × (x) (x) (y)

Factors of 9x²y² = 3 × 3 × (x) (x) (y) (y)

Factors of 12xy³ = 2 × 2 × 3 × (x) (y) (y) (y)

So the common factor is 3 × (x) (y)

Now we will take out the GCF as a factor of the given expression = 3xy (-2x² + 3xy - 4y² )

= -3xy ( 2x² - 3xy + 4y² )

Option C is the answer.

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The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

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3 years ago

What regular polygon has an interior angle of 156 degrees

icang [17]

Answer:

regular pentadecagon

Step-by-step explanation:

it has 15 sides

that is what matches the exterior angled sum property - 360degree

let me explain it

1 side = 180 - 156 = 24

360/24 = 15

mark me brainliest and thank me if you like the answer

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Leni [432]

Answer:

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Step-by-step explanation:

The step carried out was subtracting 2 from both sides.

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