Question

What is the angle of refraction if a ray leaves a material with an index of 1.66, traveling into air, and the angle of incidence is 37 deg?

Answer 1

Answer:

  $r = 21.26^0$

Explanation:

given,

light is incident on the plane surface at (i) = 37°

angle of refraction (r) = ?                        

μ is the refractive index of the  material      

      μ = 1.66      

using Snell's law                

  $\mu = \dfrac{sin i}{sin r}$                

  $1.66 = \dfrac{sin 37^0}{sin r}$                      

  $sin r = \dfrac{sin 37^0}{1.66}$    

  $sin r = 0.362$      

  $r = 21.26^0$  

hence. the angle of refraction is equal to $r = 21.26^0$