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Nana76 [90]
3 years ago
12

What was the name of charles lindbergh’s single winged airplane for his solo flight across the atlantic?

Physics
1 answer:
aev [14]3 years ago
4 0

Answer:

Spirit of St. Louis

Explanation:

Charles Lindbergh was known as a prolific aviator during the early twentieth century. He is well known for the flight he took from Long Island, New York, to Paris, France. It was a continuous flight across the Atlantic Ocean.

The plane he used was the Spirit of St. Louis which took more than 33 hours to complete the journey. It was the first successful flight of this kind. The airplane flew from Long Island on May 20 and landed in Paris on May 21.

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A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oF. The air undergoes a process to a state where the
vladimir2022 [97]

Answer:

The work and heat transfer for this process is = 270.588 kJ

Explanation:

Take properties of air from an ideal gas table.  R = 0.287 kJ/kg-k

The Pressure-Volume relation is <em>PV</em> = <em>C</em>

<em>T = C </em> for isothermal process

Calculating for the work done in isothermal process

<em>W</em> = <em>P</em>₁<em>V</em>₁ ln[\frac{P_{1} }{P_{2} }]

   = <em>mRT</em>₁ln[\frac{P_{1} }{P_{2} }]      [∵<em>pV</em> = <em>mRT</em>]

   = (5) (0.287) (272.039) ln[\frac{2.0}{1.0}]

   = 270.588 kJ

Since the process is isothermal, Internal energy change is zero

Δ<em>U</em> = mc_{v}(T_{2}  - T_{1} ) = 0

From 1st law of thermodynamics

Q = Δ<em>U  </em>+ <em>W</em>

   = 0 + 270.588

   = 270.588 kJ

4 0
3 years ago
How are strong nuclear forces and weak nuclear forces alike
Nesterboy [21]
Even tho one is stronger then the other... they are both alike because they are still nuclear forces.
6 0
3 years ago
Taste and smell are called chemical senses because:
Bingel [31]

Answer:

The answer is a," their receptors are sensitive to chemical molecules."

3 0
3 years ago
What is used to measure the speed of a moving vehicle along the road​
Romashka [77]

Answer:

Speedometer

Explanation:

Speedometer

8 0
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Read 2 more answers
A camera operator is filming a nature explorer in the Rocky Mountains. The explorer needs to swim across a river to his campsite
julia-pushkina [17]

Answer:

<em>a. Angle= 28.82°</em>

<em>b. Approved. He will get cold but he should be able to make it across</em>

Explanation:

Velocity Vector

The velocity is a physical quantity that measures how fast or slow at a particular direction some object is moving. It must be expressed as a vector with both a magnitude and direction. If the object is confined to move in one direction, then we can use the speed as the scalar (magnitude only) equivalent of the velocity.

a.

The explorer wants to swim across a river to his campsite, as shown in the image below. The river has a velocity vr and the explorer can swim at ve in still water. If he swam directly to the campsite, he would end up in a point below it because the river would push him down. He must swim with a velocity such that he overcomes the stream but he advances to its objective. Let's call the angle he must swim at respect to the shoreline to achieve his goal. The explorer's velocity can be decomposed in its rectangular components vx and vy. To overcome the river's velocity:

v_{ey}=v_r

We can compute the vertical component of the explorer's velocity as

v_{ey}=|v_e|cos\alpha

Thus

v_r=|v_e|cos\alpha

Solving for \alpha

\displaystyle cos\alpha=\frac{v_r}{|v_e|}

\displaystyle cos\alpha=\frac{0.665}{0.759}=0.876

Then we have the angle is

\alpha=28.82^o

b.

The horizontal component of the explorer's velocity is

v_{ex}=0.759sin28.82^o

v_{ex}=0.366\ m/s

This is the real velocity the explorer is having directly to the campsite

Knowing that

\displaystyle v=\frac{x}{t}

Solving for t

\displaystyle t=\frac{x}{v}

Calculating the time it takes the explorer to cross the river

\displaystyle t=\frac{29.3}{0.366}

t=80\ sec

Since this value is less than the limit value of hypothermia (300 sec), the decision is

Approved. He will get cold but he should be able to make it across

3 0
3 years ago
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