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belka [17]
3 years ago
7

A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0

seconds. What is the average acceleration of the car during those 12.0 seconds? –12.0 meters/second2
Physics
1 answer:
harkovskaia [24]3 years ago
4 0
First, we need to convert the units of the given velocity to m/sec
144 km/hr = (144 km / hr) x (1000 m / 1 km) x (1 hr / 3600 s) = 40 m/s

Now, to solve this question, we can use one of the equations of motion:
 a = (Vf - Vi) / t where:
a is the acceleration we are looking for
Vf is the final velocity of the car = 0 m/sec
Vi is the initial velocity of the car = 40 m/sec
t is the time taken = 12 seconds

Substitute with these givens in the above equation to get the acceleration as follows:
a = (0-40)/12 = -3.334 m/s^2
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Answer:

v_{i} =28.86\frac{ft}{s}

Explanation:

Conceptual analysis

We apply the kinematic formula for an object that moves vertically upwards:

(v_{f} )^{2} =(v_{i} )^{2} -2*g*y

Where:

v_{f} : final speed in ft/s

v_{i} : initial speed in ft/s

g: acceleration due to gravity in ft/s²

y: vertical position at any time in ft

Known data

For v_{f} = 25\frac{ft}{s} ,y=\frac{1}{4} h; where h is the maximum height

for y=h,  v_{f} =0

Problem development

We replace  v_{f} = 25\frac{ft}{s}  , y=\frac{1}{4} h (ft) in the formula (1),

[25^{2} =(v_{i} )^{2} -2*g*\frac{h}{4}   Equation (1)

in maximum height(h): v_{f} =0, Then we replace in formula (1):

0=(v_{i} )^{2} - 2*g*h

2*g*h=(v_{i} )^{2}

h=\frac{(v_{i})^{2}  }{2g}   Equation(2)

We replace (h) of Equation(2) in the  Equation (1) :

25^{2} =(v_{i} )^{2} -2g\frac{\frac{(v_{i})^{2}  }{2g} }{4}

25^{2} =(v_{i} )^{2} -\frac{(v_{i})^{2}  }{4}

25^{2} =\frac{3}{4} (v_{i} )^{2}

v_{i} =\sqrt{\frac{25^{2}*4 }{3} }

v_{i} =28.86\frac{ft}{s}

7 0
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Correct answer choice is :


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Explanation:


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. Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connecte
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Given :

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So, heat produced by Reem's wire is more than Nain one.

Hence, this is the required solution.

7 0
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