Okay so to represent juice we are going to use X, and to represent water we are going to use Y.
We also know that the first two starting equations are:
6x + y = 135
4x + 2y = 110
We can re-arrange the first equation so that it equals y (for now), so it is going to end up looking like this:
y = -6x +135
Now you can take that equation and plug into either one of the starting two equations. I chose the second equation. We just substitute what y equals in for y in the equation, so we have:
4x + 2(135 - 6x) = 110
Now solve
4x + 270 -12x = 110
-8x + 270 = 110
Subtract 270 from both sides
-8x = -160
Now divide by -8 on both sides
x = 20
We can now confirm that juice costs $20
Now lets plug that into the equation where we solved for y, to get the actual value of y.
y = 135 - 6(20)
y = 135 - 120
y = 15
The price of water costs $15
From this we can conclude that the cost of juice is $20 and the price of water is $15
Answer:
Step-by-step explanation:
h(x+1) = ( x + 1 - 2)²
= (x -1)²
Solving a system of equations we can see that:
They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.
<h3>
How to find how much of each candy needs to be used?</h3>
Let's define the variables:
- x = kilograms of the 40% chocolate.
- y = kilograms of the 60% chocolate.
They want to make 100kg, then:
x + y = 100
And the concentration must be of the 56%, then we can write:
x*0.4 + y*0.6 = (100)*0.56 = 56
Then we have a system of equations:
x + y = 100
x*0.4 + y*0.6 = 56
To solve this, we can isolate x on the first equation to get:
x = 100 - y
Now replace that in the other equation:
(100 - y)*0.4 + y*0.6 = 56
40 + y*0.2 = 56
y*0.2 = 16
y = 16/0.2 = 80
This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
-6.134 to +6.134
Step-by-step explanation:
given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution
X is Normal with mean =6.1 and std dev = 1 unit
We are to determine the range of values containing 70% of the population of x
We know that normal distribution curve is bell shaped symmetrical about the mean.
So to find 70% range we can use 35% on either side of the mean
Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034
Hence corresponding x value is
i.e. 70% values lie between
-6.134 to +6.134
Answer:
7 + x/8
Step-by-step explanation:
sum of 7 and Q(quorient)
7 + Q
quotient of x and 8
x/8
plus 7
7 + x/8
