What is the ordered pair for B?

A basketball player makes 8 of 22 shots in game 1, 6 of 15 shots in game 2, and 10 of 23 shots in game 3. what percent of the sh

mel-nik [20]

Answer:

40%

Step-by-step explanation:

To find the percentage in each game, you divide the number of successful shots by the number of total shots. For game 1, this looks like: 8/22 = 0.3636, or 36%.

For game 2, this give us 40%, and for game 3, 43%.

Not sure if the question is asking for a game-by-game answer or a grand total, so we'll do both. To find the total percentage over the course of the games, add all the successful shots (8 + 6 + 10 = 24) and all the attempted shots (22 + 15 + 23 = 60), and divide the same way (24 / 60 = 40%).

3 0

3 years ago

Please help me friends

adoni [48]

Answer: x ≥ 4

<u>Step-by-step explanation:</u>

x + 10 ≥ 14

Subtract 10 from both sides of the equation:

x ≥ 4

Graphing:

> and < symbols represent an open dot

≥ and ≤ symbols represent a closed dot

Since the solution is: x ≥ 4, we will use a closed dot and the arrow will point to the right of 4.

4 ·------------→

4 0

3 years ago

Last year 858 people attended the Middleton County Fair. This year 1,635 people attended. What was the percent increase from las

Pepsi [2]

Answer:

91%

Step-by-step explanation:

The first step is to calculate the increase

= 1635-858

= 777

Therefore the percent increase can be calculated as follows

= 777/858 × 100

= 0.905× 100

= 90.5 %

= 91%

Hence the percentage increase is 91%

6 0

2 years ago

A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi

blondinia [14]

Answer:

The required function is: $P(x)=-3x^2+78x-360$

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is $x-6$

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

$30-3(x-10)$

$30-3x+30$

$-3x+60$

Where x-10 represents the increase in price and 3 represents the decrease in sales per week.

Thus the profit will be:

$P(x)=(x-6)(-3x+60)$

$P(x)=-3x^2+78x-360$

Hence, the required function is: $P(x)=-3x^2+78x-360$

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: $x=\frac{-b}{2a}$

Substitute a=-3, b=78 and c=-360 in above.

$x=\frac{-78}{2(-3)}=13$

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in $P(x)=-3x^2+78x-360$

$P(x)=-3(13)^2+78(13)-360=$147$

Hence, the maximum weekly profit is $147

5 0

2 years ago

A spherical ball just fits inside a cylindrical can,16 centimeters y'all, with a diameter of 16 centimeters. What is the express

Veseljchak [2.6K]

Answer:

The correct answer is the expression of the volume of the sphere is $\frac{4}{3}$ ×π× $8^{3}$ and the expression of the volume of the leftover space is π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

Step-by-step explanation:

Height of the given cylindrical can = 16 cms.

Diameter of the given cylindrical can = 16 cms.

Now a spherical ball just fits in this given cylindrical can. Thus the diameter of the ball is equal to the diameter of the can, equal to 16 cms.

Thus the expression of the volume of ball = $\frac{4}{3}$ ×π× $r^{3}$ = $\frac{4}{3}$ ×π× $8^{3}$

Expression of the volume of the cylindrical can is π× $r^{3}$ × h = π× $8^{3}$ ×16

Expression of the leftover volume would be volume of can minus volume of the ball = π× $8^{3}$ ×16 - $\frac{4}{3}$ ×π× $8^{3}$ .

7 0

2 years ago