Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Answer:
Step-by-step explanation:
2x^2-10x+7 A=1, B=-10. C=7
-(-10)±√-10^2-4(1)(7)
------------------------------
2(1)
10±√100-28
----------------
2
10±√72
-----------
2
<u>10±8.485281374</u>
2
<u>10+8.485281374 </u>=9.24
2
<u>10-8.485281374</u> =0.76
2
Area for square = s² = 196x¹²y¹⁰z⁶
s = √(<span>196x¹²y¹⁰z⁶)
s = 14x</span>⁶y⁵z³
Perimeter = 4*s = 4*(14x⁶y⁵z³) = 56x<span>⁶y⁵z³
Perimeter = 56</span>x<span>⁶y⁵z³ D</span>
Answer:
x =3
y = 2
y= 15/8 (3) + 2
Step-by-step explanation:
