Solve for x and y. L 60° 14 (6x + 7y) M N 2(2x + 1)

Find the Least Common Multiple of these two monomials:

bonufazy [111]

LCM 14 & 24 = 168

then use the highest exponents for the variables

answer = 168x^6y^6z^8

7 0

3 years ago

carbon-14 has a half-life of 5730 years. The formula f(t)=(1/2)^t/5730 give the percentage of carbon-14 left in the item after t

andreyandreev [35.5K]

Heyy sorry I need the points

5 0

2 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0

3 years ago

Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm

tatyana61 [14]

$f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}$

3 0

3 years ago

How does the volume of a sphere with radius 2cm compare to the volume of a sphere with radius 1cm

satela [25.4K]

if you take the radius of the first and second sphere you find that they are doubled there fore the volume changed at a rate of 2 squared because 2 is what the radius was multiplied by going from the second sphere to the first so you would square what the sphere was multiplied by there fore making your answer: the volume is compares with 2 squared

5 0

3 years ago