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V125BC [204]
3 years ago
14

Please help me as fast as you can. thanks

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>

Step-by-step explanation:

In triangle DEF, we have:

<u>Given</u>:

<EDF=56

<EFD=84

So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)

____________

DE is a midsegment of triangle ACB

( since CD=DA(given)=>D is midpoint of [CD]

and BE = EA => E midpoint of [BA] )

According to midsegment Theorem,

(DE) // (CB) "//"means parallel

and DE = CB/2 = FB =CF

___________

DEBF is a parm /parallelogram.

<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))

AND DE = FB

Then, <EBF = <EDF = 56

___________

DEFC is parm.

<u>Proof</u>: (DE) // (CF) ((DE) // (CB))

And DE = CF

Therefore, <DCF = <DEF =40

___________

In triangle ACB, we have:

<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)

HOPE \:  THIS \:  HELPS.. GOOD  \: LUCK!

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This year, when Latifa and Jameel add their ages, the sum is 29. Latifa’s age is 10 less than twice Jameel’s age. The system of
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Answer:

Jameel is 13 and Laitfa is 13 x 2 - 10 = 16

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Step-by-step explanation:

The equation has already been given to us, so we just have to solve it.

According to the question,

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5 0
3 years ago
1.
Eddi Din [679]

Answer:

a) y=\dfrac{5}{2}x

b) yes the two lines are perpendicular

c) y=\dfrac{5}{4}x+6

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form y = mx + c

5y = 7 - 2x

y = \dfrac{7 - 2x}{5}

y = \dfrac{7}{5} - \dfrac{2}{5}x

y = -\dfrac{2}{5}x+\dfrac{7}{5}

this is changed into the y = mx + c, and we easily see that -2/5 is in the place of m, hence m = \frac{-2}{5} is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

m_1m_2=-1.

here both slopesm_1 and m_2 are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

\dfrac{-2}{5}m_2=-1.

m_2=\dfrac{5}{2}.

Finally, we can find the equation of the line of the perpendicular using:

(y-y_1)=m(x-x_1)

we know that the line passes through origin(0,0) and its slope is 5/2

(y-0)=\dfrac{5}{2}(x-0)

y=\dfrac{5}{2}x is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether m_1m_2=-1 ?

the slopes can be easily found through rearranging both equations to y=mx+c

Line:1

2x + 3y =6

y =\dfrac{-2x+6}{3}

y =\dfrac{-2}{3}x+2

Line:2

y = \dfrac{3}{2}x + 4

this equation is already in the form we need.

the slopes of both equations are

m_1 = \dfrac{-2}{3} and m_2 = \dfrac{3}{2}

using

m_1m_2=-1

\dfrac{-2}{3} \times \dfrac{3}{2}=-1

-1=-1

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be m=\dfrac{-4}{5} and the y-intercept is c=6 the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.

we'll first find the slope of the perpendicular using:

m_1m_2=-1

\dfrac{-4}{5}m_2=-1

m_2=\dfrac{5}{4}

we have all the ingredients to find the equation of the line now. i.e (0,6) and m

(y-y_1)=m(x-x_1)

(y-6)=\dfrac{5}{4}(x-0)

y=\dfrac{5}{4}x+6

this is the equation of the second line.

side note:

this could also have been done by simply replacing the slope(m1) of the y = − 4 / 5 x + 6 by the slope of the perpendicular(m2): y = 5 / 4 x + 6

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