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krek1111 [17]
3 years ago
7

Spending on wars is essentially categorized as government purchases. How do increases in spending on the war in Afghanistan affe

ct the aggregate demand curve?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

With the spending on wars, the aggregate demand falls and the curve will shift towards the left because the production of other goods will reduce in the economy.

<u>Explanation:</u>

When the government of a country spends on the war or the making of the weapons for the war, then the overall working of the economy is affected because the production of goods and services reduces compared to the normal production of goods and services.

With the fall in the production of the goods and the services, the demand also reduces because the overall income of the economy falls. The resources are used to produce war weapons and not consumer goods thus leading to fall in employment, income and so on. Thus the demand curve will shift to the left.

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The dingram shows a spinner innde up of a picce of card in the shape of a regular pentagon, with a toothpick pushed through its
Anastaziya [24]

Answer:

a) P(X \leq 3) = 0.99328

b) 0.6957

Step-by-step explanation:

Let X represent the number of 4's when  n = 5 independent spins

each has a probability of 0.2 (i.e p = 0.2)

This notation is represented as:

X \approx Binomial (n = 5, p = 0.2)

Probability of  x  number of 4's is:

P(X=x)= (\left \ n \atop x \right) p^x (1-p)^{(n-x)}

here; (\left \ n \atop x \right) is the combinatorial expression

(\left \ n \atop x \right) = \frac{n!}{x!(n-x)!}

P(X \leq3), n =5 , p = 0.2

P(X \leq3) = 1-P(X > 3)

So; let's first find:

P(X > 3)

= P(3

P(X = 4) =( \left \ {{5} \atop {4}} \right. ) (0.2)^4 (1-0.2)^1  \\ \\ P(X = 4) = 5(0.2)^4(0.8)^1 \\ \\ P(X = 4) = 0.0064

P(X = 5) =( \left \ {{5} \atop {5}} \right. ) (0.2)^5 (1-0.2)^0  \\ \\ P(X = 5) = 5(0.2)^5(0.8)^0 \\ \\ P(X = 5) = 0.00032

P (X=4)+P(X  = 5 ) \\ \\  = 0.0064 + 0.00032 = 0.006720  \\ \\ \approx 0.007

P(X > 3 ) = 0.00672 \\ \\ P(X \leq 3) = 1- P(X > = 3 ) \\ \\ =1 - 0.00672  \\ \\ = 0.99328

P(X \leq 3) = 0.99328

b)

Given that:

The ratio of boys to girls at birth in  Singapore is quite high at 1.09:1

What proportion of Singapore families with exactly 6 children will have at least 3 boys?

Probability of having a boy = \frac{1.09}{1+1.09} = 0.5215

Binomial Problem with n = 6

P(3<= x <=6) = 1 - P(0<= x <=2)

= 1 - binomial (6,0.5215,2)

= 0.6957

5 0
3 years ago
The average value of a function f over the interval [−1,2] is −4, and the average value of f over the interval [2,7] is 8. What
Anna71 [15]

The average value of a continuous function f(x) over an interval [a, b] is

\displaystyle f_{\mathrm{ave}[a,b]} = \frac1{b-a}\int_a^b f(x)\,dx

We're given that

\displaystyle f_{\rm ave[-1,2]} = \frac13 \int_{-1}^2 f(x) \, dx = -4

\displaystyle f_{\rm ave[2,7]} = \frac15 \int_2^7 f(x) \, dx = 8

and we want to determine

\displaystyle f_{\rm ave[-1,7]} = \frac18 \int_{-1}^7 f(x) \, dx

By the additive property of definite integration, we have

\displaystyle \int_{-1}^7 f(x) \, dx = \int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx

so it follows that

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(\int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx\right)

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(3\times(-4) + 5\times8\right)

\displaystyle f_{\rm ave[-1,7]} = \boxed{\frac72}

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3 years ago
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To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.

In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.

A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).

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Find the value of x if p ll q​
Stolb23 [73]

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