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Aleksandr [31]
3 years ago
7

For football tryouts at a local school, 12 coaches and 42 players will split into groups. Each group have the same number of coa

ches and players. What is the greatest number of groups that can be formed? How many coaches and players will be in each of these groups?
Mathematics
2 answers:
aev [14]3 years ago
8 0

There will be 6 groups with 2 coaches and 7 players in each group.

melamori03 [73]3 years ago
4 0
<span>The biggest number of groups that can be formed is 6, because six is the greatest common factor of 12 and 42. There will be 2 coaches in each group because 6 x 2 = 12 and 7 players in each group because 7 x 6 = 42.</span>
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Multiply 2 and 3 also multiply 4 and 5 and then divide the products together like so 2x3 divided by 4x5   so 6 divided by 20
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3 years ago
Write the first 4 terms of the arithmetic sequence With first term 37 and common difference 9
alexandr402 [8]

Answers:

first term = 37

second term = 46

third term = 55

fourth term = 64

==========================================

Explanation:

Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.

first term = 37

second term = 37+9 = 46

third term = 46+9 = 55

fourth term = 55+9 = 64

-----------

The nth term formula is

a(n) = 9n+28

It can be found by plugging a = 37 and d = 9 into the general form

a(n) = a + d*(n-1)

4 0
3 years ago
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Step-by-step explanation:

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4 years ago
The ratio of money in Terry's bank account to Faye's bank account was 3:5.
inn [45]

Answer:

<em>Terry had £780 initially and Faye had £1300</em>

Step-by-step explanation:

<u>System of Equations</u>

We'll call the following variables:

x = Terry's balance in his bank account

y = Faye's balance in her bank account

The initial relation between them is:

\frac{x}{y}=\frac{3}{5}

Cross-multiplying:

5x = 3y        [1]

If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus

x + 220 = y - 300

Subtracting 220:

x = y - 520         [2]

Substituting in [1]

5(y - 520) = 3y

Multiplying:

5y - 2600 = 3y

Adding 2600 and subtracting 3y:

2y = 2600

Dividing by 2:

y = 1300

From [2]:

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7 0
3 years ago
Reduce 7y + 2y 2 - 7 by 3 - 4y.
NARA [144]

Answer:

D. 2y^2+11y-10.

Step-by-step explanation:

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We need to reduce 7y+2y^2-7 by 3-4y

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

2y^2+7y-7  ⇒ equation 1

Also Arranging other equation we get;

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Now we will subtract equation 2 from equation 1 we get;

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Hence the reduce form of the given equation is 2y^2+11y-10.

7 0
3 years ago
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