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3 years ago

3(x-8) = -29.7 please solve for x

Mathematics

1 answer:

GrogVix [38]3 years ago

6 0

Answer:

The answer is x= -1.9.

Use the 3 to multiply the number and the letter in the bracket... which is...

3x-24=-29.7.

3x=-29.7+24.

3x=-5.7.

x=-5.7/3.

x=-1.9.

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An object is thrown upward from the top of a 192 ft building with an initial velocity of 64 feet

Airida [17]

Answer:

t=6

Step-by-step explanation:

ground height = 0

(are you sure your formula is correct? isn't it - 16t²?)

if h=16t² +64t+192 is true then

16t² +64t+192 = 0

t² + 4t + 12 = 0

t = (-4 ± √(4² - 4*12)) / 2*1 = (-4 ± √-32) / 2 = -2 ± 2√-2

There is no solution of t

if it is h= - 16t² +64t+192

0 =- 16t² + 64t + 192

t² - 4t - 12 = 0

(t + 2) (t -6) = 0

t should be positive

t = 6 sec

7 0

3 years ago

Solve the equation y = ax - b for the variable a.

lorasvet [3.4K]

Answer:

y-b/x = a

Step-by-step explanation:

y-b/x = a

7 0

3 years ago

HELP! IM STUCK!

Readme [11.4K]

Answer:

$(x-1)^2+(y+4)^2=9$

Step-by-step explanation:

The equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

The center of the circle is (1, -4).

And the radius is 3.

Substitute:

$(x-(1))^2+(y-(-4))^2=(3)^2$

Simplify. Thus, our equation is:

$(x-1)^2+(y+4)^2=9$

3 0

3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

3 0

2 years ago

One positive number is 3 more than twice another. If their product is 629, find the numbers.

Soloha48 [4]

Answer:

17,37

Step-by-step explanation:

one number = x

The positive number = 2x + 3

x * (2x+3) = 629

x*2x + x *3 = 629

2x² + 3x - 629 = 0

2x² - 34x + 37x - 17*37 =0

2x*(x -17) + 37(x - 17) = 0

(x - 17)(2x + 37) = 0

x - 17 = 0 ; Ignore 2x + 37 as s is a positive number

x = 17

Positive number = 2*17 +3 = 34+3 = 37

5 0

3 years ago