Let's solve ~
![\qquad \sf \dashrightarrow \:[( 8 \sdot3) + (8 \sdot2i) + (5i \sdot3) + (5i \sdot2i)] -[( 4 \sdot4) + (4 \sdot - i) + (i \sdot4) + (i \sdot - i)]](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%5B%28%208%20%5Csdot3%29%20%2B%20%288%20%5Csdot2i%29%20%2B%20%285i%20%5Csdot3%29%20%2B%20%285i%20%5Csdot2i%29%5D%20-%5B%28%204%20%5Csdot4%29%20%2B%20%284%20%5Csdot%20-%20i%29%20%2B%20%28i%20%5Csdot4%29%20%2B%20%28i%20%5Csdot%20-%20i%29%5D)
![\qquad \sf \dashrightarrow \:[24+ 16i + 15i+ 10i {}^{2} ] -[16 - 4 i+ 4i - i {}^{2} ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%5B24%2B%2016i%20%2B%2015i%2B%2010i%20%7B%7D%5E%7B2%7D%20%5D%20-%5B16%20-%204%20i%2B%204i%20-%20i%20%7B%7D%5E%7B2%7D%20%5D)
![\qquad \sf \dashrightarrow \:[24+ 31i+ 10 {}{( - 1)} ] -[16 - ( - 1){}^{} ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%5B24%2B%2031i%2B%2010%20%7B%7D%7B%28%20-%201%29%7D%20%5D%20-%5B16%20-%20%28%20-%201%29%7B%7D%5E%7B%7D%20%5D)
![\qquad \sf \dashrightarrow \:[24+ 31i - 10 {}{} ] -[16 + 1{}^{} ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%5B24%2B%2031i%20-%2010%20%7B%7D%7B%7D%20%5D%20-%5B16%20%20%2B%201%7B%7D%5E%7B%7D%20%5D)
![\qquad \sf \dashrightarrow \:[14+ 31i {}{} ] -[17{}^{} ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%5B14%2B%2031i%20%7B%7D%7B%7D%20%5D%20-%5B17%7B%7D%5E%7B%7D%20%5D)
I hope you understood the procedure ~
Answer:
Step-by-step explanation:
4y = 2(y - 5) - 2
4y = 2y - 10 - 2
4y - 2y = -12
2y = -12
y = -12/2
y = -6 <===
There is the graphing method, completing the square, factoring, and my favorite, the quadratic formula
There would be seventy rows, going to the right. Each row would be 35 high. hope it helped.
Answer:
x = 25 degrees.
Step-by-step explanation:
By the external angle of a triangle theorem x + <C = 50
But x = <C ( alternate angles).
Therefore 2x = 50
x = 25.
