28, by the way you could’ve just used a calculator
Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
Answer:C
Step-by-step explanation:
Answer:The formula is P=2 L=2 W or V= L x W X H
Step-by-step explanation:
Answers:
10.) 
9.) 
8.) 
7.)
6.) 
Step-by-step explanations:
10.) 
9.) ![\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B3%5D%7B135%7D%7D%7B%5Csqrt%5B3%5D%7B40%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B3%5D%7B3%5Cfrac%7B3%7D%7B8%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%5B3%5D%7B5%7D%7D%7B2%5Csqrt%5B3%5D%7B5%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B1%5Cfrac%7B1%7D%7B2%7D%7D)
8.) ![\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B4%5D%7B162%7D%7D%7B%5Csqrt%5B4%5D%7B32%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B4%5D%7B5%5Cfrac%7B1%7D%7B16%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B%5Cpm%7B3%5Csqrt%5B4%5D%7B2%7D%7D%7D%7B%5Cpm%7B2%5Csqrt%5B4%5D%7B2%7D%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cpm%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7D)
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6.) 
I am joyous to assist you at any time.
