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Likurg_2 [28]
3 years ago
15

.60 is what percent of 180? ​

Mathematics
2 answers:
Lynna [10]3 years ago
7 0

Answer:

1.08

Step-by-step explanation:

.60% *180=108

108/100=1.08%

icang [17]3 years ago
3 0

Answer:

108

Step-by-step explanation:

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If there are 9 shirts and 8 pants, how many possible outfits
Elena L [17]

Answer:

Uhh Like 50 different outfits using the same paints and shirts just put differently

Step-by-step explanation:

4 0
2 years ago
What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?
lesya [120]

Answer:

F27

Step-by-step explanation:

5 0
3 years ago
A rectangular garden has a perimeter of 172 feet. The length of the garden is 24 feet more than the width. What are the dimensio
Lilit [14]
Given width is 24 less than length.
W=L-24
Perimeter = 2(W+L)=2(L-24+L)=4L-48 
But we're also given perimeter = 172'
Therefore 4L-48=172
solve for L
4L=172+48=220
L=55'
W=55-24 =  31'
Check: Perimeter = 2(W+L)=2(31+55)=2*86=172'  good!

Answer: The dimensions of the garden are 31' * 55'
6 0
3 years ago
The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo
Aloiza [94]

Answer:

a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]

Step-by-step explanation:

a. -Given that:

n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator,\bar x_m-\bar x_f is calculated by the following following:

\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

-And the margin of error, E at a 99% confidence can be calculated as:

E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

#We substitute to solve for the confidence interval using the standard deviation and sample size values in  a above:

CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0
2 years ago
Jason has 20 coins composed of nickels and dimes. If the total value is $1.10 how many coins of each does he have
SOVA2 [1]

Answer:

Jason has 10 dimes and 2 nickels

because each dime equals 10 cent

and each nickel equals 5 cent

10×10= 100

2×5= 10

100+10= 110 add the decimal =$1.10

6 0
3 years ago
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