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2 years ago

11

2035x = 7626.9923/2

1 answer:

fomenos2 years ago

3 0

Answer:

X = ejpp formula

Step-by-step explanation:

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Simplify the expression by combining like terms<br>-7k-3+8j+4j-3k+18

Nutka1998 [239]

Answer:

-10k+12j+15

Step-by-step explanation:

-7k-3+8j+4j-3k+18

-7k-3k+8j+4j-3+18

-10k+12j+15

If you're satisfied with the answer, then please mark me as Brainliest.

3 0

2 years ago

Hamzah's soccer team is trying to raise $620 to travel to a tournament in Florida, so they decided to host a pancake breakfast.

Kobotan [32]

Answer:

31 people

Step-by-step explanation:

Hamzah soccer team is trying to raise the amount of $620 to travel to a tournament in Florida

The soccer team decide to organise a pancake breakfast

Each person that attends the breakfast must pay $20

Therefore the amount of people needed to attend the breakfast to raise $620 can be calculated as follows

= 620/20

= 31

Hence 31 people need to be in attendance inorder to raise $620

5 0

3 years ago

the temperature was 15 .it dropped so that the temperature was 0 . what integer represents the change in temperature?

Nataliya [291]

Answer:

if the temperature was at 15 and dropped to zero the amount it changed would be is -15. The integer is -15 because an integer is a whole number and it can also be a negative or positive number it just can not be a fraction

3 0

2 years ago

a swimmer swam 48 kilometers in d days. What is the value of the d if the swimmer swam an average of 3.2 kilometers daily?

lianna [129]

Time= distance/speed

=48/3.2= 15

6 0

3 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .

So that is, the distance between $A$ and $B$ is:

$\frac{-1+\sqrt{65}}{8}-\frac{-1-\sqrt{65}}{8}$

$\frac{-1+\sqrt{65}+1+\sqrt{65}}{8}$

$\frac{2\sqrt{65}}{8}$

$\frac{\sqrt{65}}{4}$

If we compare this to $\frac{\sqrt{m}}{n}$ , we should see that:

$m=65 \text{ and } n=4$ .

So $m-n=65-4=61$ .

5 0

2 years ago

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