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2 years ago

(8x-12) (3x+5)=360 Can y’all please help me solve this problem. It is a polygon theorem

Mathematics

1 answer:

Lorico [155]2 years ago

5 0

Answer:

360 polygon

Step-by-step explanation:

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White a proportian . SHow the solution 8/3= 2/n

snow_tiger [21]

Answer: 3/4 I’m pretty sure. I looked at it and got confused so not 100% sure.

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3 years ago

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Dominic invests £1000 in a bank account which has a simple interest rate of 4% per annum. He would like to work out how much mon

mestny [16]

Answer:

ooytot

Step-by-step explanation:

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3 years ago

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(1+tanx)/(sinx+cosx)=secx

jek_recluse [69]

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ is proved

<h3><u>Solution:</u></h3>

Given that,

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ ------- (1)

First we will simplify the LHS and then compare it with RHS

$\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}$ ------ (2)

$\text {We know that } \tan x=\frac{\sin x}{\cos x}$

Substitute this in eqn (2)

$=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

On simplification we get,

$=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}$

$=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}$

Cancelling the common terms (sinx + cosx)

$=\frac{1}{c o s x}$

We know secant is inverse of cosine

$=\sec x=R . H . S$

Thus L.H.S = R.H.S

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$

Hence proved

5 0

3 years ago

Using the order of operations, what would be the first step:<br><br> 4−8÷1−3[3+(7−5)2]

jeka94

Answer:

(7-5)

Step-by-step explanation:

According to PEMDAS, parenthesis go first. But there are two sets of parenthesis so the one inside the other goes first.

Next would be [3+(2*2)]

Then, [3+4]

Then, -8/1

Then, -3(7)

So the question would be 4-8-21

Which gives you -25 as an answer.

I realize that you weren't asking for the whole thing but maybe there are follow up questions.

3 0

3 years ago

Algebra 1 question 4.

Brrunno [24]

Greetings!

To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.

<u>Proof:</u> <em>3-1=2, 5-3=2</em>

The first, consecutive, odd number: $x$

The second, consecutive, odd number: $x+2$

The third, consecutive, odd number: $x+4$

The fourth, consecutive, odd number: $x+6$

The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

$3((x)+(x+2))=(x+6)-35$

Complete the operations inside the parenthesis:

$3(2x+2)=(x+6)-35$

Distribute the parenthesis (utilizing the distributive property)

$(((2x)(3))+((2)(3)))=(x+6)-35$

$(6x+6)=(x+6)-35$

Simplify both sides:

$6x+6=x-29$

Add -6 and -x to both sides of the equation:

$(6x+6)+(-6)+(-x)=(x-29)+(-6)+(-x)$

$5x=-35$

Divide both sides of the equation by 5:

$\frac{5x}{5}=\frac{-35}{5}$

$x=-7$

If $x$ is equal to -7:

$x+2=-5$

$x+4=-3$

$x+6=-1$

The four numbers are:

$\boxed{-7,-5,-3,-1}$

I hope this helps!

-Benjamin

4 0

3 years ago

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