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RUDIKE [14]
3 years ago
6

G(x) = -2x^3 - 12x^2 + 30x + 200

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

you have a cubic function right? what are you trying to do?? find intercepts?? need a little more information

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A lottery ticket costs $2.00 and a total of 4 500 000 tickets were sold. The prizes are as follows:
ser-zykov [4K]
$9000000 you do this by doing 4,500,000*2 you can do this working it out or calculator
5 0
4 years ago
Help me please!!
Mice21 [21]

Answer:

1.) - 1/2

2.) the slope is 0 which means it is a vertical line

Step-by-step explanation:

In order to solve this you take the formula

y-y / x-x

and put they y value and x value of each equation in

7 0
3 years ago
Conservationists tagged 120 ​black-nosed rabbits in a national forest in 1990. In 1991​, they tagged 240 ​black-nosed rabbits in
Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year  time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value  and k exponential constant and t be time period.

So

Y=Y0e^(kt)

Here Y=240  ,Y0=120  t=1 year time period

So

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120,  t=9  ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

8 0
4 years ago
In a journey of 15 miles, two third distance was travelled with 40 mph and remaining with 60 mph. How much time does the journey
Ad libitum [116K]

The first step in solving this question is to split the journey into 2 parts. In the first part of the journey, \frac{2}{3} \times 15 = 10 miles are covered at a speed of 40 mph. In the second part the journey 5 miles are covered at a speed of 60 mph.

The equation to compute the time of a journey  given the speed and distance is t=\frac{d}{s} where t is the time, s is the speed and d is the distance.

The time for the first part of the journey is calculated as shown below,

t=\frac{d}{t} \\t=\frac{10m}{40mph} =\frac{10}{40} h.

The time for the second part of the journey is calculated as follows,

t=\frac{d}{t} \\t=\frac{5m}{60mph} =\frac{5}{60} h.

The total time is the sum of the times taken to cover each part of the journey and is calculated as shown below,

t=\frac{10}{40} h+\frac{5}{60} =\frac{30+10}{120} h=\frac{40}{120}h =\frac{1}{3} h

The time to cover the journey is a third of an hour or 20 minutes.

5 0
3 years ago
Evaluate the function g(x) = –2x2 + 3x – 5 for the input values –2, 0, and 3.
Genrish500 [490]

Answer:

 g(-2) = -15, g(0) = -9, g(3) = -18

Step-by-step explanation:

g(-2) = -2*2 + 3(-2) - 5 g(-2) = -4 - 6 - 5g(-2) = -15g(0) = -4 - 0 - 5g(0) = -9g(3) = -4 - 3(3) - 5g(3) = -4 - 9 - 5g(3) = -18

I HOPE THIS HELPS

4 0
2 years ago
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