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weeeeeb [17]
3 years ago
15

A farmer planted 2/5 of his forty acres in corn and another 3/10 of his land in wheat. Taken together, what fraction of the 40 a

cres had been planted in corn or wheat?
Mathematics
1 answer:
Reil [10]3 years ago
4 0

rewrite the fractions so the have the same denominator ( bottom number)

Multiply 2/5 by 2 to get 4/10

Now you can add 4/10 and 3/10 to make 7/10.


7/10 of the land is corn or wheat.

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a student found the volume of a rectangular pyramid with a base area of 92 square meters and a height of 54 Meters to be 4968 cu
Naya [18.7K]
It is not correct. 

The student found the volume by multiplying the base area with the height. He forgot to divide it by 3.

Formula to find the volume of the pyramid = 1/3 base area x height

volume = 1/3 x 92 x 54 = 1656 square meters 
6 0
3 years ago
Read 2 more answers
How to find the circumference of a cirlcle
Otrada [13]
\sf{Circumference = 2\times\pi\times~r}

Where r is the radius of the circle.
7 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
Find the domain and range of the<br>function y = f(x)= √x-2<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%202%7D%20" i
Over [174]

Answer:

3x-x+2=4

Step-by-step explanation:

The domain of f(x)=2^x would be the x values. This would include all values that you can input as x in order to make this problem work. The domain of a function is usually all real numbers. The range of f(x)=2^x would be the y values. This would include all values that would be the output for the y value. An example of this would be if you used 2 as x then the function would read f(x)=2^2. The y would equal 4 which would be included in the range of this function. To find the domain and range of the inverse you would follow the proper steps to get the inverse of the function which would be x=2^y. The domain would be the x values and the range would be the y values. If you put 4 as x which would be your input for the domain you would get 2^4 = 16 for the y which would be the range.

4 0
2 years ago
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