Answer:

Step-by-step explanation:
This question is on rules of rational exponential
where the exponential is a fraction, you can re-write it using radicals where the denominator of the fraction becomes the index of the radical;
<u>General expression </u>
![a^\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
Thus ![\sqrt[3]{x} =x^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3Dx%5E%5Cfrac%7B1%7D%7B3%7D)
<u>Applying the same in the question </u>
![\sqrt[3]{x^5y} =x^\frac{5}{3} y^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3Dx%5E%5Cfrac%7B5%7D%7B3%7D%20y%5E%5Cfrac%7B1%7D%7B3%7D)
=
Answer:
(a) (6, 2)
Step-by-step explanation:
The system of equations has one of them in y= form, so it lends itself to solution by substitution.
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Using the equation for y to substitute into the first equation, we have ...
2x -y = 10
2x -(-1/2x +5) = 10 . . . . . substitute for y
2x +1/2x -5 = 10 . . . . . eliminate parentheses
5/2x = 15 . . . . . . . . . add 5, collect terms
x = 6 . . . . . . . . . . . multiply by 2/5
Using the equation for y, we have ...
y = -1/2(6) +5 = -3 +5
y = 2
The solution is (x, y) = (6, 2).
log(4) + log(2) - log(5)
= log(2²) + log(2) - log(5)
= 2 log(2) + log(2) - log(5)
= 3 log(2) - log(5)
= log(2³) - log(5)
= log (2³/5)
= log (8/5)
= log (1.6) = 0.2041... (rounded)