Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
<span>(4x ÷ 2) - 9y
is difference of two terms.</span>
Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:

Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:

Required
Determine the solution set

Open Both Brackets


Collect Like Terms


Multiply both sides by -1

Hence, the solution set is 
Answer:
I found out the answer, it's 2/3
Step-by-step explanation:
I hope that helped!