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3 years ago

Factor the trinomial below.

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

Answer:

its D

Step-by-step explanation:

Dont even trip I just did the test ;)

liberstina [14]3 years ago

5 0

after you use the FOIL method (just multiplying everything) you'll get x^2 - 8x - 5x + 40. now just add the like terms

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Find the derivative of <img src="https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20x" id="TexFormula1" title="tan^{-1} x" alt="tan^{-1} x

sladkih [1.3K]

$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

$\frak {\huge{ \frac{1}{1 + {x}^{2} } }}$

Step-by-step explanation:

$\sf let \: f(x) = { \tan }^{ - 1} x \\ \\ \sf f(x + h) = { \tan}^{ - 1} (x + h)$

$\sf f'(x) = \frac{f(x+h) - f(x) }{h}$

$\sf \implies \lim_{ h \to 0 } \frac{ { \tan }^{ - 1}(x + h) - { \tan}^{ - 1}x }{h} \\ \\ \\ \sf \implies \lim_ {h \to 0} \frac{ { \tan}^{ - 1} \frac{x + h - x}{1 + (x + h)x} }{h}$

By using

$\sf { \tan}^{ - 1} x - { \tan}^{ - 1} y = \\ \sf { \tan}^{ - 1} \frac{x - y}{1 + xy} formula$

$\sf \implies \large \lim_{h \to0 } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{h} \\ \\ \\ \sf \implies \large{\lim_{h \to0} } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } \times (1 + hx + {x}^{2} )} \\ \\ \\ \sf \implies \large \lim_{h \to0} \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } } + \lim_{h \to0} \frac{1}{1 + hx + {x}^{2} }$

Now putting the value of h = 0

$\sf \large \implies 0 + \frac{1}{1 + 0 + {x}^{2} } \\ \\ \\ \purple{ \boxed { \implies \frac{1}{1 + {x}^{2} } }}$

6 0

2 years ago

Order the side lengths from least to greatest

Liula [17]

Answer:

BC < CE < BE < ED < BD

Step-by-step explanation:

In the triangle BCE,

m∠BEC + m∠BCE + m∠CBE = 180°

m∠BEC + 81° + 54° = 180°

m∠BEC = 180 - 135

m∠BEC = 45°

Order of the angles from least to greatest,

m∠BEC < m∠CBE > mBCE

Sides opposite to these sides will be in the same ratio,

BC < CE < BE ----------(1)

Now in ΔBED,

m∠BEC + m∠BED = 180°

m∠BED = 180 - 45

= 135°

Now, m∠BDE + m∠BED + DBE = 180°

11° + 135°+ m∠DBE = 180°

m∠DBE = 180 - 146

= 34°

Order of the angles from least to greatest will be,

∠BDE < ∠DBE < ∠BED

Sides opposite to these angles will be in the same order.

BE < ED < BD ----------(2)

From relation (1) and (2),

BC < CE < BE < ED < BD

7 0

3 years ago

6multiplied by 3 to the -2nd power minus 3 to the fourth power multiplied by 9 plus 4 to the 0th power

Contact [7]

Answer in fraction form is -2182/3
Answer in decimal form is -727.3*
Answer in Mixed number form -737 1/3

5 0

3 years ago

Please help this is timed

elena-14-01-66 [18.8K]

Answer:

option d is correct

de=9 and ef=15

6 0

3 years ago

Read 2 more answers

Complete a table with at least 5 points then graph the following quadratic on the coordinate plane. Identify all zeros.y = -2x2

Anna [14]

Answer:

See attached

Step-by-step explanation:

Given function:

y = -2x² + 5x + 8

Table and graph are attached

Zeros are included in the graph

Zero's are obtained:

x = 0 ⇒ y = 8

y = 0 ⇒ Solving quadratic equation

-2x² + 5x + 8 = 0
x = (-5 ± √(25 + 2*4*8))/-4
x = 3.608
x = -1.108

So zeros are (0, 8), (3.608, 0) and (-1.108, 0)

3 0

3 years ago