Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
Answer:
$0.025x² . . . where x is a number of percentage points
Step-by-step explanation:
The multiplier for semi-annual compounding will be ...
(1 + x/2)² = 1 + x + x²/4
The multiplier for annual compounding will be ...
1 + x
The multiplier for semiannual compounding is greater by ...
(1 + x + x²/4) - (1 + x) = x²/4
Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.
If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...
$250·(x/100)² = $0.025x² . . . where x is a number of percentage points
_____
<u>Example</u>:
For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.
The answer should be 1 3/8
Answer:
Step-by-step explanation:
Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .
<u>Given</u><u> </u><u>:</u><u>-</u>
•
<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>
•
<u>Proof </u><u>:</u><u>-</u><u> </u>
We know that ,
Therefore , here substituting the value of sinA , we have ,
Simplify the whole square ,
Add the numbers in numerator ,
Multiply it by 2 ,
Take out 2 common from the numerator ,
Simplify ,
Subtract the numbers ,
Simplify,
Hence Proved !
The parent function is y = x^2
There is a compression of 3:
y = 3x^2
There is a shift by 1 unit to the left:
y = 3(x + 1)^2