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3 years ago

1+x+x²please explain

Mathematics

1 answer:

oee [108]3 years ago

4 0

What is the question?

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A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for

wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

Fee for 1 event = $4

Fee for x events = $4x

Joining fee remains constant. So, the total fee is

$y=28+4x$

Substitute x=4 in this equation.

$y=28+4(4)$

$y=28+16$

$y=44$

Therefore, total cost of 4 events is $44.

8 0

2 years ago

There are 3 seats in each row in a school auditorium. There are 15 rows in the auditorium. Each new seat costs $74. What is the

Akimi4 [234]

3 seats x 15 rows = 45 total seats

45 seats x $74 = $3,330.00 total cost

6 0

3 years ago

The average of four numbers is 98. If three of the numbers are 86,87,and 91 what is the fourth number?

timurjin [86]

To find the average, you have to add all the numbers up and then divide by the amount of numbers you added together.

Equation: (86+87+91+x)/4=98
Solve for x:
86+87+91+x=98*4
264+x=392
x=392-264
x=128

The fourth number is 128

7 0

3 years ago

Write the trigonometric expression in terms of sine and cosine, and then simplify.

katrin2010 [14]

Hello,

tan t /(sec t -cos t)= sin t/(cos t *(1/cos t -cos t))
=sin t/(cos t*(1-cos ²t)/cos t))
=sin t/sin² t=1/sin t [or=cosec t.]

3 0

3 years ago

A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%

andre [41]

Answer: a) 683 b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}$

a) Given : Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=\pm1.96$

Margin of error : $E=0.03$

Formula to calculate the sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683$

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067$

Hence, the required sample size would be 1067 .

3 0

3 years ago

1+x+x²please explain​

1+x+x²please explain