Answer:
6. B. x + 8
7. D. ( 3x-2)(3x-2)
8. D. Perfect square trimomal 
9.C. x - 2
10. A. 3x and 8x
Step-by-step explanation:
Semoga Bermanfaat 
 
        
             
        
        
        
Answer:
11
Step-by-step explanation:
Solution for this problem is in this picture.
 
        
             
        
        
        
Arc length is s=r x theta. The unit circle has r=1 so for an arc length of 3pi/2 the angle is 3pi/2 radians
        
             
        
        
        
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Given that a unshaded rectangle is inscribed in a shaded circle.
- Diameter of the circle d = 13m
- Radius r = d/2 = 13m/2 = 6.5m
- Dimension of length of the rectangle l = 12m
- Dimension of width of the rectangle w = 5m
- Area of the shaded region As = ?
First we calculate the area of the shaded circle.
A = πr² =  π × ( 6.5m )²
A = 132.665m²
Area of the shaded circle is 132.665m².
Area of the unshaded rectangle will be;
A = l × w
A = 12m × 5m
A = 60m²
Area of the unshaded rectangle is 60m².
Now, area of the shaded region will be;
= Area of the shaded circle - Area of the unshaded rectangle
= 132.665m² - 60m²
= 132.665m² - 60m²
= 72.67m²
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Learn more about area polygons here: brainly.com/question/22590672
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The answer to 187=1/2*17(6+X) is X=16