Answer:
Step-by-step explanation:
If you want to determine the domain and range of this analytically, you first need to factor the numerator and denominator to see if there is a common factor that can be reduced away. If there is, this affects the domain. The domain are the values in the denominator that the function covers as far as the x-values go. If we factor both the numerator and denominator, we get this:

Since there is a common factor in the numerator and the denominator, (x + 3), we can reduce those away. That type of discontinuity is called a removeable discontinuity and creates a hole in the graph at that value of x. The other factor, (x - 4), does not cancel out. This is called a vertical asymptote and affects the domain of the function. Since the denominator of a rational function (or any fraction, for that matter!) can't EVER equal 0, we see that the denominator of this function goes to 0 where x = 4. That means that the function has to split at that x-value. It comes in from the left, from negative infinity and goes down to negative infinity at x = 4. Then the graph picks up again to the right of x = 4 and comes from positive infinity and goes to positive infinity. The domain is:
(-∞, 4) U (4, ∞)
The range is (-∞, ∞)
If you're having trouble following the wording, refer to the graph of the function on your calculator and it should become apparent.
f(x) = 4x + 3
That's one-to-one, a linear function that will give a different f(x) for each different x.
For the inverse let's swap x and y and solve for y
x = 4y + 3
x - 3 = 4y
y = (x- 3)/4
That's the inverse,
Answer: (x- 3)/4, second choice
The domain and range of the inverse is all real numbers. It's two lines; I'll leave the graphing to you.
Multiply and add it up and you got ur answer
Answer:
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens
Step-by-step explanation:
To form the image of an object using a convex lens, ray diagrams are used. The following steps are followed when drawing ray diagrams.
1) Light rays are drawn from the object incidented on the lens and parallel to the principal axis. The incident light refracts (bends) through the lens and converges at the focal point at the other side of the lens.
2) Another incident light passes through the optical centre undeflected and intersect with the refracted ray at the other side of the lens.
Based on the above points, Roshan made an error by drawing the ray that goes parallel to the main axis and after passing through the lens made the same ray to be parallel from the object to the lens instead of refracting (bending) after passing through the lens.
Do u have a pic of the problem?